Answer:
Last option: It is not a function because there are two different y-values for a single x-value.
Step-by-step explanation:
It is necessary to remember that, by definition, a relation is a function if each input value (x-value) has one and only one output value (x-value) .
In this case, the following points:
You can observe that the input value 4 (
) has two ouput values. These are:
Therefore, since there are two different y-values for a single x-value, you can conclude that the given graph is not a function.
Answer:
69.1
Step-by-step explanation:
<em>Mean height of 14 students = 69.0 inches</em>
<em>Mean = sum of data/number of data</em>
<em>69 = sum of data/14</em>
<em>sum of data = 966</em>
<u>FOR NEW MEAN:</u>
<em>Height of additional student = 70.5</em>
Mean = sum of data/ number of data
Mean = 966+70.5/14+1
Mean = 1036.5/15
Mean = 69.1
Therefore, the mean height of the 15 students in the class is 69.1
Answer: E(Y) = 1.6 and Var(Y)=1.12
Step-by-step explanation:
Since we have given that
X 0 1 2
P(X) 0.4 0.4 0.2
Here, number of games = 2
So, 
Since 
are independent variables.
so, ![E[Y]=2E[X]\\\\Var[Y]=2Var[X]](https://tex.z-dn.net/?f=E%5BY%5D%3D2E%5BX%5D%5C%5C%5C%5CVar%5BY%5D%3D2Var%5BX%5D)
So, we get that
![E(X)=0.4\times 0+0.4\times 1+0.2\times 2=0.8\\\\and Var[x]=E[x^2]-(E[x])^2\\\\E[x^2]=0\times 0.4+1\times 0.4+4\times 0.2=1.2\\\\So, Var[x]=1.2-(0.8)^2\\\\Var[x]=1.2-0.64=0.56](https://tex.z-dn.net/?f=E%28X%29%3D0.4%5Ctimes%200%2B0.4%5Ctimes%201%2B0.2%5Ctimes%202%3D0.8%5C%5C%5C%5Cand%20Var%5Bx%5D%3DE%5Bx%5E2%5D-%28E%5Bx%5D%29%5E2%5C%5C%5C%5CE%5Bx%5E2%5D%3D0%5Ctimes%200.4%2B1%5Ctimes%200.4%2B4%5Ctimes%200.2%3D1.2%5C%5C%5C%5CSo%2C%20Var%5Bx%5D%3D1.2-%280.8%29%5E2%5C%5C%5C%5CVar%5Bx%5D%3D1.2-0.64%3D0.56)
So, E[y]=2×0.8=1.6
and Var[y]=2×0.56=1.12
Hence, E(Y) = 1.6 and Var(Y)=1.12
Answer:
4 shelves
Step-by-step explanation:
if there is 8 shelves that display 1 car then that means there is 8 cars total.
so if you need a total of 12 cars then you would do (total of cars needed - total of cars you have).
(12-8) which would equal 4.
you need 4 cars left but on each shelf going forward needs to have 2 cars on it.
now since you have 4 cars you would divide that by the amount of cars on each shelf going forward.
4/2) which equals 2.
you need 2 more shelfs for the 4 cars needed.
