The slope:
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 8 2 ) / ( 3 - 2 ) = 6 / 1
m = 6 ( we have the same slope for AB and A`B` )
AB = √[( 3 - 2 )² + ( 8 - 2 )²] = √37
A`B` = 3.5 √37 = 21.29
The graph of the function f(x)=(x+2)(x+6) is shown
The statement the function is negative for all real values of x where x <-2
<span>The expression given (27x^2)z/(-3x^2)(z^6), can be simplify as below:
By properties of powers, if you have the same base, you can substract the exponents. Then:
=(</span>27x^2)z/(-3x^2)(z^6)
=-9z/z^6 (As you can see: x^2-2= x^0=1)
=-9/z^5 (Then, z^6-1=z^5)
<span>
Therefore, the answer is: The exponent on the variable z is 5.</span>
Answer:
-22
Step-by-step explanation:
6j-5k=11
5j-6k=22
-----------------
5(6j-5k)=5(11)
-6(5j-6k)=-6(22)
-----------------------
30j-25k=55
-30j+36k=-132
-----------------------
11k=-77
k=-77/11
k=-7
6j-5(-7)=11
6j+35=11
6j=11-35
6j=-24
j=-24/6
j=-4
------------------
2j+2k=2(-4)+2(-7)=-8-14=-22
Answer:
<h3>AC=96 units.</h3>
Step-by-step explanation:
We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.
, and CE=6x .
<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>
Therefore, AE = EC.
Plugging expressions for AE and EC, we get

Subtracting 6x from both sides, we get


Factoriong quadratic by product sum rule.
We need to find the factors of -16 that add upto -6.
-16 has factors -8 and +2 that add upto -6.
Therefore, factor of
quadratic is (x-8)(x+2)=0
Setting each factor equal to 0 and solve for x.
x-8=0 => x=8
x+2=0 => x=-2.
We can't take x=-2 as it's a negative number.
Therefore, plugging x=8 in EC =6x, we get
EC = 6(8) = 48.
<h3>AC = AE + EC = 48+48 =96 units.</h3>