1) From the measure of 40°, you can write:
tan(40°) = 100/x, where x is the base from the building to the tower
⇒x=100/tan(40°) = 119,18 m
2) From the measure of 30°, you can write
tan(30°) = y / 119,18, where y is the height from the roof of Jill's building to the top of the tower.
Then, y = tan(30°) * 119,18 = 68,81 m
3) The height of Jill's building is 100 - 68,81 = 31,19 m
Answer:
Distance: 435.9 ft
Step-by-step explanation:
This is a right triangle shown in the picture.
To solve for 
, we can use trigonometry.
The 35° angle's opposite side is 250 ft and the hypotenuse of the triangle is (what we are seeking to find).
The ratio that relates opposite and hypotenuse is sine.
<em>We know that,</em>
<em>Thus we can write:</em>
<em>Cross multiplying and solving for gives us:</em>
Second answer choice is right: 435.9 ft
Answer:
58 degrees
Step-by-step explanation:
90 - 32 = 58
<em>Greetings from Brasil...</em>
We need to use the Sine Law in Any Triangle....
(AB/SEN C) = (BC/SEN A)
19/SEN X = 16/SEN32
SEN X = 0,62
<em>using the sine arc</em>
ARC SEN 0,62 ≈ 39
Answer:
a) 0.88
b) 0.35
c) 0.0144
d) 0.2084
e) 0.7916
Step-by-step explanation:
a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88
b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.
c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.
d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084
e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916
