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Alexeev081 [22]
2 years ago
5

JL is a diameter of circle K. if tangents to circle K are construvted through points L and J, what relationship would exist betw

een the two tangents? explian

Mathematics
1 answer:
Allisa [31]2 years ago
7 0
Check the picture below.

notice, the left-hand-side of the picture is the tangents segment theorem, both tangents are the same length and the point of tangency, in red, is always a right-angle, however note that they're touching a radius segment, not a diameter one, and the radii lines are slanted some.

notice the right-hand-side of the picture, the points of tangency at J and L are right-angles, and the two tangents at those points, will simply be parallel, and never touch each other.

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I hope this helps you out

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Answer:

E(X) = 1.28

Var(X) = 0.6016

E(X | Y=2) = 1.6667

Var(X | Y=2) = 0.4272

Step-by-step explanation:

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A doctor recommends a two-step process to treat a rare form of pancreatic cancer. The first method is successful 80% of the time
Rudiy27

Answer:

The answer is 15%.

Step-by-step explanation:

The probability that:

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       80% x 90% = 72%

  • The first method is a success, but the second one is not:

        80% x (1 - 90%) = 8%

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Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
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Answer:

C. hyperbola; 9x^2-25y^2-250y-850=0

Step-by-step explanation:

The given conic has equation:

9x^2-25y^2=225

Divide through by 225.

\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}

\frac{x^2}{25}-\frac{y^2}{9}=1

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

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Multiply through by 225.

9(x-0)^2-25(y-5)^2=225

Expand

9x^2-25(y^2-10y+25)=225

9x^2-25y^2+250y-625=225

Rewrite in general form;

9x^2-25y^2+250y-625-225=0

9x^2-25y^2+250y-850=0

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Answer:24%

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