JL is a diameter of circle K. if tangents to circle K are construvted through points L and J, what relationship would exist betw
een the two tangents? explian
1 answer:
Check the picture below.
notice, the left-hand-side of the picture is the tangents segment theorem, both tangents are the same length and the point of tangency, in red, is always a right-angle, however note that they're touching a radius segment, not a diameter one, and the radii lines are slanted some.
notice the right-hand-side of the picture, the points of tangency at J and L are right-angles, and the two tangents at those points, will simply be parallel, and never touch each other.
notice, the left-hand-side of the picture is the tangents segment theorem, both tangents are the same length and the point of tangency, in red, is always a right-angle, however note that they're touching a radius segment, not a diameter one, and the radii lines are slanted some.
notice the right-hand-side of the picture, the points of tangency at J and L are right-angles, and the two tangents at those points, will simply be parallel, and never touch each other.
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Answer:
And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:
Where a is the constant or the initial amount, b te base and x the independnet variable (time)
For this special case we know that:
And 500 represent the constant or initial value for the function
Step-by-step explanation:
We have the following function given:
And we want to know what repreent the value 500 for this equation. If we see the general expression for an exponential function we have:
Where a is the constant or the initial amount, b te base and x the independnet variable (time)
For this special case we know that:
And 500 represent the constant or initial value for the function
The firts thig we are going to do is create tow triangles using the angles of elevation of Paul and Jose. Since the problem is not giving us their height we'll assume that the horizontal line of sight of both of them coincide with the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as
.
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
Now we can use the law of sines to find the distance between Paul and Jose:
Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
We can conclude that Jose is 33.9m from the base of the tree.
We know that Paul is 19m from the base of the tree and its elevation angle to the top of the tree is 59°. We also know that the elevation angle of Jose and the top of the tree is 43°, but we don't know the distance between Paul of Jose, so lets label that distance as
Now we can build a right triangle between Paul and the tree and another one between Jose and the tree as shown in the figure. Lets use cosine to find h in Paul's trianlge:
Now we can use the law of sines to find the distance
Now that we know the distance between Paul and Jose, the only thing left is add that distance to the distance from Paul and the base of the tree:
We can conclude that Jose is 33.9m from the base of the tree.