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mestny [16]
2 years ago
5

Ayesha works as a real estate agent. Her annual gross salary is $28,000. From this, she must pay 20% income tax on anything earn

ed above $15,000. In addition, she must repay a loan at a rate of $140 per month, which is taken out of her post-tax pay (i.e. after the tax has been calculated). What is Ayesha's take home pay per year? Round your answer to the nearest dollar.
Mathematics
1 answer:
Lady bird [3.3K]2 years ago
8 0

Answer:

Step-by-step explanation:

Annual gross salary = $28000

Income tax = 20% on anything above $15000

So she's taxable for $5000

Rent loan = $140 per month = $140 * 12= $1680 per annum

Tax deductible per annum = 20% of $5000

20 / 100 * $5000 = $1000

Total amount she takes home per annum =

Gross salary per annum - tax - loan =

($28000 - $1000 - $1680) = $25,320

Ayesha takes home $25,320 home annually.

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ella [17]

$30 + $35 = $65

Assuming tax is on whole sale not each item:
$65 * 0.06 (6%) = $3.90 (6% of $65)

$65 + $3.90 = $68.90 ($65 + 6%)

OR

You could combine both of these steps and just use this working:
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4 0
2 years ago
Which term of the AP. 8 , -4 , -16 , -28 ,......... is -880 ?​
denis-greek [22]

Answer:

75th term

Step-by-step explanation:

hope it is well understood

6 0
1 year ago
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Consider a disease whose presence can be identified by carrying out a blood test. Let p denote the probability that a randomly s
kifflom [539]

Answer:

The expected number of tests, E(X) = 6.00

Step-by-step explanation:

Let us denote the number of tests required by X.

In the case of 5 individuals, the possible value of x are 1, if no one has the disease, and 6, if at least one person has the disease.

To find the probability that no one has the disease, we will consider the fact that the selection is independent. Thus, only one test is necessary.

Case 1: P(X=1) = [P (not infected)]⁵

                       = (0.15 - 0.1)⁵

            P(X=1) = 3.125*10⁻⁷

Case 2: P(X=6) = 1- P(X=1)

                        = 1 - (1 - 0.1)⁵

               P(X=6) = (1 - 3.125*10⁻⁷) = 0.999999

               P(X=6) = 1.0

We can then use the previously determined values to compute the expected number of tests.

E(X) = ∑x.P(X=x)

      = (1).(3.125*10⁻⁷) + 6.(1.0)

 E(X)  =  E(X) = 6.00

Therefore, the expected number of tests, E(X) = 6.00

3 0
1 year ago
∆ABC and ∆FDE are congruent by the criterion. (Use the three-letter abbreviation without spaces.)
Anastasy [175]

Answer:

x = 11, y = 8

Step-by-step explanation:

ΔABC and ΔFDE are congruent by the postulate SSS

Equate the congruent sides in the 2 triangles

BC = ED, that is

x + 3 = 14 ( subtract 3 from both sides )

x = 11

-------------------------------------

DF = AB, that is

x - y = 3 ← substitute x = 11

11 - y = 3 ( subtract 11 from both sides )

- y = 3 - 11 = - 8 ( multiply both sides by - 1 )

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6 0
1 year ago
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Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
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Answer:

a) the sample size (n) = 156.25≅ 156

Step-by-step explanation:

<u>Step1 </u>:-

Given the two sample sizes are equal so n_{1} =n_{2} = n

Given the standard error (S.E) = 0.04

The standard error of the proportion of the given  sample size

S.E = \sqrt{\frac{pq}{n} }

Step 2:-

here we assume that the proportion of boys and girls are equally likely

p= 1/2 and q= 1/2

S.E = \sqrt{\frac{p(1-p)}{n} } \leq \frac{\frac{1}{2} }{\sqrt{n} }

\sqrt{n} = \frac{\frac{1}{2} }{S.E}

squaring on both sides, we get

n = \frac{1}{(2X0.04)^{2} }

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Standard error = 0.04

4 0
1 year ago
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