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Tanya [424]
1 year ago
13

Imani is flying a drone. It takes off from a height of 24 feet above the ground and rises at a constant rate of 4.5 feet per sec

ond. Imani is trying to get it high enough above the ground to see the Hudson River. The drone must be at least 330 feet above the ground.
Mathematics
2 answers:
gogolik [260]1 year ago
7 0

Answer:

330=(4.5x)+24

Step-by-step explanation:

330=(4.5x)+24

-24               -24    subtract 24 from each side

306=4.5x

/4.5   /4.5              divide by 4.5

68 seconds

Firdavs [7]1 year ago
6 0

Answer:

It will take 73 seconds.

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which right triangle’s unknown leg measures is 43 square root units ? Assume the given length are in the same unit of measure.
Ahat [919]

Answer:

4th opinion

Step-by-step explanation:

4 0
2 years ago
The length of a rectangular rug is 4 feet less than twice its width. The perimeter of the rug is 40 feet. Write a system of equa
Brrunno [24]

Answer:

Step-by-step explanation:

L=2W-4

40=2L+2W

The first equation uses the information that the length of a rectangular rug is 4 feet less than twice its width.

The second equation is using your standard perimeter equation of 2L+2W=perimeter of a rectangle.

Hope this is helpful :)

6 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
3 With 72 million bicycles, correct to the
Galina-37 [17]

Answer:

  181 million km

Step-by-step explanation:

"Correct to the nearest unit" means the actual value might be 1/2 unit larger (or smaller) than the reported value.

The upper bound would be the product of the maximum number of bicycles and the maximum distance each travels:

  (72.5 · 10^6 bicycles)(2.5 km/bicycle) = 181.25 · 10^6 km

__

Since the given numbers are good to 2 significant figures (or so), we might reasonably put the upper bound as 180·10^6 km.

5 0
2 years ago
A researcher took a random sample of 100 students from a large university. She computed a 95% confidence interval to estimate th
katen-ka-za [31]

Answer:

Part (A): The correct option is true.

Part (B): The null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

Step-by-step explanation:

Consider the provided information.

Part (A)

A random sample of 100 students from a large university.

Increasing the sample size decreases the confidence intervals, as it increases the standard error.

If the researcher increase the sample size to 150 which is greater than 100 that will decrease the confidence intervals or the researcher could produce a narrower confidence interval.

Hence, the correct option is true.

Part (B)

The researcher wants to identify that whether there is any significant difference between the measurement of the blood pressure.

Therefore, the null and alternative hypothesis should be:

H_o: \mu =0 ; H_a:\mu \neq0

7 0
2 years ago
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