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2 years ago

15

A collection of quarters and nickels contains at least 42 coins and is worth at most $8.00. If the collection contains 25 quarte

rs, how many nickels can be in the collection? Let x = the number of quarters. Let y = the number of nickels. There are at least nickels, but no more than nickels.

2 answers:

Elenna [48]2 years ago

9 0

Answer:

17

35

Step-by-step explanation:

KIM [24]2 years ago

5 0

Answer:

17

35

Step-by-step explanation:

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612/6=102
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dangina [55]

Step-by-step explanation:

The given objective function is $C = 60x + 85y$

To check that which ordered pair is minimizing the objective function-we will substitute all the ordered pair one by one in the given function and we will calculate the value of C. The ordered pair which will give the minimum value will be the answer.

For (0, 160)

$C=60\times 0+85\times 160=13600$

For (55, 70)

$C=60\times 55+85\times 70=9250$

For (80, 50)

$C=60\times 80+85\times 50=9050$

For (80, 50)

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Hence the ordered pair which minimizes the objective function is (80, 50)

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CaHeK987 [17]

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Step-by-step explanation:

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