Answer:
OPtion I is right
Step-by-step explanation:
Once we know sin of an angle, and it lies in II quadrant, we know that
cos, sec, tan and cot would be negative but csc will be positive.
So use the fact that
Thus cos is obtained using negative square root.
Now tan = sin/cos, and sec = 1/cos:
cot =1/tan and csc =1/sin
Thus all value can be obtained easily
So option I
Answer:
BD = 4.99 units
Step-by-step explanation:
Consider the triangle ABD only.
The angle formed is 31 degrees which occurs between two sides that are AD and BC.
We know that for a right angled triangle, the angle can always be taken as an angle between hypotenuse and base.
Thus, The perpendicular sides is then 3 units, where base is BD and Hypotenuse is AD
Using formula for tanθ
tanθ = Perpendicular/Base
tan31 = 3/BD
0.601 = 3/BD
BD = 3/0.601
BD = 4.99 units
Answer:
Step-by-step explanation:
The given measurements determine one triangles, A = 61Á, a =
23, b = 24 because the triangle can be defined using those 3 data, first is
using the sine law to solve another angle. Then using cosine law to solve the
third side. Lastly solving the 3rd angle by difference.
