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seropon [69]
2 years ago
13

Arthur borrowed $2,100 from the bank. 3 years later, Arthur owes the bank $2,478. What was the percentage rate of simple interes

t on the loan?
Mathematics
2 answers:
ASHA 777 [7]2 years ago
7 0

Answer:

Percentage Rate=6%

Step-by-step explanation:

Total borrowed=$2,100

Time=3 years

Rate=?

Total amount owed after 3 years= total borrowed + simple interest

$2,478=$2,100 + x

X=$2,478 - $2,100

=$378

The simple interest=$378

Simple interest=P×R×T

Where,

P= principal=$2,100

R=Rate=?

T=Time=3 years

Simple interest=$378

Simple interest=P×R×T/100

$378=$2,100×R×3/100

$378=$6,300R/100

$378=$63R

R=$378/$63

R=6

Therefore,

Rate=6%

Dovator [93]2 years ago
5 0

Answer:12

Step-by-step explanation:

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The first answer is correct, if you go back by 5% each year you will see that.

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2 years ago
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Which graph represents the solution set for the quadratic inequality x2 + 2x + 1 > 0?
ipn [44]

Answer:

We have to determine the graph of the given inequality as:

x^2+2x+1>0

on solving this equation we get:

(x+1)^2>0

Since we know that:

(x+1)^2=x^2+1^2+2\times x\times 1\\\\(x+1)^2=x^2+1+2x

Now we know that when x=-1 the value of:

(x+1)^2=0

Also for the value other than -1 the function being a quadratic function will always give a non-zero positive value.

Hence, range of the function in intervals could be written as:

(-∞,-1)∪(-1,∞).

Hence, the graph of the function will be the whole of the number line with a open circle on -1.

5 0
1 year ago
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after taking nine test Carols average grade in her Italian classes 90 her teacher drops the lowest of the nine test scores to de
Ostrovityanka [42]

Answer:

82

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5 0
2 years ago
Out of every $100 that Judy earns at her part time job, she saves $25 for college. The amount she saves is directly proportional
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6 0
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Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
1 year ago
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