Start from the end. 5+4*2. Which in turn equals 18 inches.
Answer:
Step-by-step explanation:
Given that a group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below.
Data set is as ollows:
70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

H0: mu = 60 sec
Ha: mu not equals 60 sec
Mean diff = 2.27

Test statistic = 2.27/SE =0.4815
p value =0.6376
Since p>0.05, we accept null hypothesis
i.e. there is statistical evidence to say that students are reasonably good at estimating one minute
Step One
Subtract 32 from both sides.
F - 32 = 9/5(k - 273.15)
Step Two
Multiply by 5/9 on both sides.
5/9*(F - 32) = 5/9 * 9/5 (k - 273.15)
5/9*(F - 32) = k - 273.15
Step Three.
Add 273.15 to both sides.
5/9*(F - 32) + 273.15 = k
Problem B
F = 180
<em><u>Solve</u></em>
5/9*(F - 32) + 273.15 = k
5/9*(180 -32) + 273.15 = k
5/9*148 + 273.15 = k
82.2222 + 273.15 = k
355.37 = k
k = 355.4 <<< Answer