We are looking for the probability :

Transform the law to standard normal like this:

The above formula is equivalent to this one:

From normal law table, we read the value of

.

Solving the above equation for the score n:


, it is the score we are looking for.
I’m pretty sure the answer is test
System 1: The solution is (x, y) = (-4, 5)
System 2: The solution is 
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
2x + 3y = 7 ------ eqn 1
-3x - 5y = -13 --------- eqn 2
We can solve by elimination method
Multiply eqn 1 by 3
6x + 9y = 21 ------ eqn 3
Multiply eqn 2 by 2
-6x - 10y = -26 ------- eqn 4
Add eqn 3 and eqn 4
6x + 9y -6x - 10y = 21 - 26
-y = -5
y = 5
Substitute y = 5 in eqn 1
2x + 3(5) = 7
2x + 15 = 7
2x = -8
x = -4
Thus the solution is (x, y) = (-4, 5)
<h3><em><u>
Second system of equation is:</u></em></h3>
8 - y = 3x ------ eqn 1
2y + 3x = 5 ----- eqn 2
We can solve by susbtitution method
From given,
y = 8 - 3x ----- eqn 3
Substitute eqn 3 in eqn 2
2(8 - 3x) + 3x = 5
16 - 6x + 3x = 5
3x = 16 - 5
3x = 11

Substitute the above value of x in eqn 3
y = 8 - 3x

Thus the solution is 
Answer: 
Step-by-step explanation:
You know that for weekdays parking the price is $3.50 and weekends are half price. Then for weekends, the price is the following:

You know that Cindy parked in the garage 20 times per month, and three of these days were weekend days. This means that she parked 17 times in week days and 3 times in weekends days.
Therefore, the total amount of money she would spend on parking per month can be calculated with:
