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viktelen [127]
2 years ago
14

A scientist is studying red maple tree growth in a state park. She measured the trunk diameters of a sample of trees in the same

month every other year. The tables show the data for two of the trees. This is the final year in which she will collect data. When her data collection is complete, she will predict future red maple tree growth. In year 13, the scientist will put tree wrap around tree 1 to protect it from the winter snow. The height of the tree wrap needs to be 45 inches. The wrap is priced by the square foot. To the nearest square foot, how many square feet of wrap does she need? A. 22 B. 44 C. 121 D. 261
Mathematics
2 answers:
Tems11 [23]2 years ago
7 0

Answer:

(A) 22

Step-by-step explanation:


Genrish500 [490]2 years ago
3 0
The answer will beee (A.22)
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Most graduate business schools require applicants to take the gmat. scores on this test are approximately normally distributed w
Harman [31]
We are looking for the probability :
P(X > n)=0.05
Transform the law to standard normal like this:
P(\dfrac{X-545}{100}> \dfrac{n-545}{100})=0.05
The above formula is equivalent to this one:
P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
From normal law table, we read the value of \dfrac{X-545}{100}.
\dfrac{X-545}{100}=1.7
Solving the above equation for the score n:
X-545=170
X=715, it is the score we are looking for. 
5 0
2 years ago
Allen and Beverly thought of the same number. Allen doubled the number and added 15 to the result. He got 51. Beverly performed
pishuonlain [190]
<h2><em>Bev got 66 for her number.</em></h2>
8 0
2 years ago
Which of the following assessment types has the greatest effect on your overall grade?
frutty [35]
I’m pretty sure the answer is test
3 0
2 years ago
CL 6-131. Solve each system using the method of your choice.
shepuryov [24]

System 1: The solution is (x, y) = (-4, 5)

System 2:  The solution is (x, y) = (\frac{11}{3}, -3)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 7 ------ eqn 1

-3x - 5y = -13 --------- eqn 2

We can solve by elimination method

Multiply eqn 1 by 3

6x + 9y = 21 ------ eqn 3

Multiply eqn 2 by 2

-6x - 10y = -26 ------- eqn 4

Add eqn 3 and eqn 4

6x + 9y -6x - 10y = 21 - 26

-y = -5

y = 5

Substitute y = 5 in eqn 1

2x + 3(5) = 7

2x + 15 = 7

2x = -8

x = -4

Thus the solution is (x, y) = (-4, 5)

<h3><em><u>Second system of equation is:</u></em></h3>

8 - y = 3x ------ eqn 1

2y + 3x = 5 ----- eqn 2

We can solve by susbtitution method

From given,

y = 8 - 3x ----- eqn 3

Substitute eqn 3 in eqn 2

2(8 - 3x) + 3x = 5

16 - 6x + 3x = 5

3x = 16 - 5

3x = 11

x = \frac{11}{3}

Substitute the above value of x in eqn 3

y = 8 - 3x

y = 8 - 3 \times \frac{11}{3}\\\\y = 8 - 11\\\\y = -3

Thus the solution is (x, y) = (\frac{11}{3}, -3)

4 0
2 years ago
Cindy’s parking garage charges $3.50 for weekday parking, and weekends are half price. If Cindy parked in the garage 20 times pe
Pachacha [2.7K]

Answer: \$64.75

Step-by-step explanation:

  You know that for weekdays parking the price is $3.50 and weekends are half price.  Then for weekends, the price is the following:

\frac{\$3.50}{2}=\$1.75

You know that Cindy parked in the garage 20 times per month, and three of these days were weekend days. This means that she parked 17 times in week days and 3 times in weekends days.

 Therefore, the total amount of money she would spend on parking per month can be calculated with:

Total\ per\ month=17(\$3.50)+3(\$1.75)\\\\Total\ per\ month=\$59.5+\$5.25\\\\Total\ per\ month=\$64.75

6 0
2 years ago
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