Positive 14/472 (because of rise over run when finding slope)
Well for the first one it'd be y=3x+50 and for the second one it'd be y=10x
Answer:
1) ΔCBF ≅ ΔCDF by (SSS)
2) ΔBFA ≅ ΔDFE by (SAS)
3) ΔCBE ≅ ΔCDA by (HL)
Step-by-step explanation:
1) Since BC ≅ DC and DF ≅ BF where CF ≅ CF (reflective property) we have;
ΔCBF ≅ ΔCDF by Side Side Side (SSS) rule of congruency
2) Since DF ≅ BF and FA ≅ FE where ∠DFE = ∠BFA (alternate angles)
Therefore;
ΔBFA ≅ ΔDFE by Side Angle Side (SAS) rule of congruency
3) Since FA ≅ FE and DF ≅ BF then where EB = FE + BF and AD = FA + DF
Where:
EB and AD are the hypotenuse sides of ΔCBE and ΔCDA respectively
We have that;
EB = AD from FE + BF = FA + DF
Where we also have BC ≅ DC
Where:
BC and DC are the legs of ΔCBE and ΔCDA respectively
Then we have the following relation;
ΔCBE ≅ ΔCDA by Hypotenuse Leg (HL).
Ok...so 2/4 = 1/2 or 0.5.....and u want a fraction with a denominator of 6 greater then this...
3/6 is not greater, it is equal....so try 4/6.......4/6 = 0.66....so it is greater then 2/4 and has a denominator of 6
This is the concept of algebra, to get the values of the unknown we proceed as follows:
Length=(2w-30) cm
width=w
Area=length×width
=w(2w-30)=5400
=2w^2-30w=5400
hence
2w^2-30w-5400=0
solving the quadratic we get:
w^2-15w-2700=0
thus
(w+45)(w-60)=0
hence
w=-45 or w=60
since there is no negative dimension we shall take w=60
thus the value of w=60