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algol13
2 years ago
10

Which of the following are steps in multiplying fractions? Multiply the numerators. Divide the numerator by the denominator. Mul

tiply the denominators. Flip the second fraction. Simplify the result, if possible.
Mathematics
2 answers:
aksik [14]2 years ago
8 0
You times the numerator by the numerator and the denominator by the denominator
thats all
DiKsa [7]2 years ago
7 0

Answer: 1, 3, and 5 are your answers.


Step-by-step explanation: Multiplication of fractions in arithmetic follows a rather simple rule. Multiply the numerators together and the denominators together and reduce the resulting fraction, if possible.


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A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel
Serjik [45]

The answer is B. 5P5 x 20P15.

This is because to make the second grade students to sit in the first row we have 5 seats and 5 students so we will permute the 5 students to those 5 seats. So 5P5.

Now we are left with 20 seats and 15 first grade students so we can simply permute those 15 students into those 20 seats. So 20P15.

Finally using the counting rule principle we will multiply both of these so 5P5 x 20P15.

7 0
2 years ago
Read 2 more answers
Evaluate the triple integral ∭ExydV where E is the solid tetrahedon with vertices (0,0,0),(5,0,0),(0,9,0),(0,0,4).
Elan Coil [88]

Answer: \int\limits^a_E {\int\limits^a_E {\int\limits^a_E {xy} } \, dV = 1087.5

Step-by-step explanation: To evaluate the triple integral, first an equation of a plane is needed, since the tetrahedon is a geometric form that occupies a 3 dimensional plane. The region of the integral is in the attachment.

An equation of a plane is found with a point and a normal vector. <u>Normal</u> <u>vector</u> is a perpendicular vector on the plane.

Given the points, determine the vectors:

P = (5,0,0); Q = (0,9,0); R = (0,0,4)

vector PQ = (5,0,0) - (0,9,0) = (5,-9,0)

vector QR = (0,9,0) - (0,0,4) = (0,9,-4)

Knowing that cross product of two vectors will be perpendicular to these vectors, you can use the cross product as normal vector:

n = PQ × QR = \left[\begin{array}{ccc}i&j&k\\5&-9&0\\0&9&-4\end{array}\right]\left[\begin{array}{ccc}i&j\\5&-9\\0&9\end{array}\right]

n = 36i + 0j + 45k - (0k + 0i - 20j)

n = 36i + 20j + 45k

Equation of a plane is generally given by:

a(x-x_{0}) + b(y-y_{0}) + c(z-z_{0}) = 0

Then, replacing with point P and normal vector n:

36(x-5) + 20(y-0) + 45(z-0) = 0

The equation is: 36x + 20y + 45z - 180 = 0

Second, in evaluating the triple integral, set limits:

In terms of z:

z = \frac{180-36x-20y}{45}

When z = 0:

y = 9 + \frac{-9x}{5}

When z=0 and y=0:

x = 5

Then, triple integral is:

\int\limits^5_0 {\int\limits {\int\ {xy} \, dz } \, dy } \, dx

Calculating:

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx

\int\limits^5_0 {\int\limits {\int\ {xy(\frac{180-36x-20y}{45} - 0 )}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0 {\int\ {180xy-36x^{2}y-20xy^{2}}  \, dy } \, dx

\frac{1}{45} \int\limits^5_0  {90xy^{2}-18x^{2}y^{2}-\frac{20}{3} xy^{3} } \, dx

\frac{1}{45} \int\limits^5_0  {2430x-1458x^{2}+\frac{94770}{125} x^{3}-\frac{23490}{375}x^{4}  } \, dx

\frac{1}{45} [30375-60750+118462.5-39150]

\int\limits^5_0 {\int\limits {\int\ {xyz}  \, dy } \, dx = 1087.5

<u>The volume of the tetrahedon is 1087.5 cubic units.</u>

3 0
2 years ago
Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her
vazorg [7]
Well, from what you’ve posted, it seems that a negative value cannot be accepted since that would imply she has gone underwater. She also cannot go above 300 feet since she is going downwards from a max height.
5 0
2 years ago
Read 2 more answers
Tomer owns a daycare center called kidz kare. One afternoon he collected the age of each person in kidz kare. The following hist
tatuchka [14]

Answer:

3/10

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Write the fraction in ascending order.​
sveta [45]

from most to least:

i: 1/2, 1/3, 1/7, 1/10

ii: 2/3, 2/5, 2/9, 2/11

iii: 5/6, 3/4, 2/3, 1/2

iv: 4/5, 3/4, 5/8, 1/2

7 0
2 years ago
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