P = 52% = 0.52
SE = sqrt(p(1 - p)/n) = sqrt(0.52(1 - 0.52)/65) = sqrt((0.52 x 0.48) / 65) = sqrt(0.00384) = 0.0620
Let x be a random variable representing the percent of girls in the sample, then
P(x > 0.70) = 1 - P(x < 0.70) = 1 - P(z < (0.70 - 0.52) / 0.0620) = 1 - P(z < 2.905) = 1 - 0.99816 = 0.00184
The probability that there will be more than 70% of girls in the sample is 0.00184. Therefore, it will be unusual for more than 70% of them to be girls.
Draw the picture and label the
width = w
The length of the monitor is six times the quantity of five less than half its width:
length = 6(w/2-5)
length = 3w-30
Area = (length)*(width)
384=(3w-30)*(w)
384=3w^2-30w
Answer:
the dimensions of the monitor in terms of its width is:
384=3w^2-30w
<span>In general, the students increased their standardized math scores from 5th grade to 7th grade. The students might be more familiar with the exam and they have learned more in their math classes.</span>
Answer:
6 cups
Step-by-step explanation: 8oz = 1 cup 6 *8=48 or
48/8= 6
F(x)=3x/2 for 0≤x≤2
<span>.....=6 - 3x/2 for 2<x≤4 </span>
<span>g(x) = -x/4 + 1 for 0≤x≤4 and g'(x)=-1/4 </span>
<span>so h(x)= f(g(x)) = (3/2)(-¼x+1)=-3x/8 + 3/2 for 0≤x≤2 </span>
<span>for x=1, h'(x)=-3/8 so h'(1)=-3/8 </span>
<span>When x=2, g(2)=1/2 so h'(2)=g'(2)f '(1/2)= -(1/4)(3/2)=-3/8 </span>
<span>When x=3, h(x)=6 - (3/2)(1 - x/4) = 9/2 +3x/8 </span>
<span>h'(x)=3/8 so h'(3) = 3/8</span>
