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Vikki [24]
2 years ago
15

If the ordinate is three more than twice the abscissa and x {-1, 0, -}, which of the following sets of ordered pairs satisfies t

he given conditions? {(-1, 1), (0, 3), (-, )} {(-1, 1), (0, 3), (-, )} {(-1, -1), (0, 3), (-, 1)}
Mathematics
2 answers:
Ahat [919]2 years ago
8 0

Yeah Bro Its The First One Whoever Wrote Or Typed The Question Typed The Wrong 2 Option Choice So Your Right Its A.) {(-1, 1), (0, 3), (-1/3,7/3 )}

Greeley [361]2 years ago
7 0
The abscissa is the x-coordinate of the ordered pair and the ordinate is the y-coordinate. The ordered pair is therefore given to be,
   (abscissa, ordinate)
or (x , y)

From the given, it is stated that the ordinate is three more than twice the abscissa. The ordered pair can therefore be written as,
  
  (x, 2x + 3)

If x = -1 then,
  y = 2(-1) + 3 = 1
Ordered pair : (-1, 1)

If x = 0
  y = 2(0) + 3 = 3
Ordered pair : (0, 3)

Hence, the answer to this is either the first choice or the second choice which appears to be just the same. 
You might be interested in
A random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a st
Orlov [11]

Answer:

95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

Step-by-step explanation:

We are given that a random sample of 250 students at a university finds that these students take a mean of 15.2 credit hours per quarter with a standard deviation of 2.3 credit hours.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                          P.Q. = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample credit hours per quarter = 15.2 credit hours

             s = sample standard deviation = 2.3 credit hours

             n = sample of students = 250

             \mu = population mean credit hours per quarter

<em>Here for constructing 95% confidence interval we have used One-sample t test statistics as we know don't about population standard deviation.</em>

So, 95% confidence interval for the population mean, \mu is ;

P(-1.96 < t_2_4_9 < 1.96) = 0.95  {As the critical value of t at 249 degree of

                                        freedom are -1.96 & 1.96 with P = 2.5%}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u><em>95% confidence interval for</em></u> \mu = [ \bar X-1.96 \times {\frac{s}{\sqrt{n} } } , \bar X+1.96 \times {\frac{s}{\sqrt{n} } } ]

                  = [ 15.2-1.96 \times {\frac{2.3}{\sqrt{250} } } , 15.2+1.96 \times {\frac{2.3}{\sqrt{250} } } ]

                  = [14.915 hours , 15.485 hours]

Therefore, 95% confidence interval for the mean credit hours taken by a student each quarter is [14.915 hours , 15.485 hours].

<em>The interpretation of the above confidence interval is that we are 95% confident that the true mean credit hours taken by a student each quarter will be between 14.915 credit hours and 15.485 credit hours.</em>

8 0
1 year ago
A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports
hichkok12 [17]

Answer:

1

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

2

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

3

t  =  3.054

4

The p-value  is   p-value  =  P(Z >  3.054) = 0.0011291

5

The conclusion is  

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is  

Step-by-step explanation:

From the question we are told that

   The first sample size is  n_1  =  51

    The first sample  mean is \mu_1  =  36

    The second sample size is  n_2  =  41

    The second sample  size is  \mu_2  =  25

     The first standard deviation is  \sigma _1  =  21.4 \  g

    The second standard deviation is  \sigma _2  =  12.8 \  g

  The  level of significance is  \alpha =  0.05

The  null hypothesis is  H_o  :  \mu_1 = \mu_ 2

The  alternative hypothesis is  H_a :  \mu_1 > \mu_2

Generally the test statistics is mathematically represented as

    t  =  \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1}  + \frac{s_2^2}{n_2}  } }

=>   t  =  \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51}  + \frac{ 12.8^2}{41}  } }

=> t  =  3.054

The  p-value is mathematically represented as

     p-value  =  P(Z >  3.054)

Generally from the z table  

             P(Z >  3.054) =  0.0011291

=>   p-value  =  P(Z >  3.054) = 0.0011291

From the values obtained  we see that p-value  < \alpha so  the null hypothesis is rejected

Thus the conclusion is  

  There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0
2 years ago
If m angle BGF=152 degrees, what is m angle AGF
Allushta [10]

The Answer is: 64 degrees

4 0
2 years ago
Read 2 more answers
An observer from the top of a lighthouse 370 feet above sea level sees two sailboats in the water. The angles of depression to t
noname [10]

Answer:the sailboats are 358 feet apart.

Step-by-step explanation:

The diagram of the triangle representing the situation is shown in the attached photo.

B represents the position of the lighthouse.

D represents the position of the first sailboat.

C represents the position of the second sailboat.

x represents the distance between the two sailboats

We would apply trigonometric ratio

Tan # = opposite/adjacent

For triangle ABD,

Tan 12 = 370/AD

AD = 370/Tan 12 = 370/0.2126 = 1740.357 feet

For triangle ABC,

Tan 10 = 370/AC

AD = 370/Tan 10 = 370/0.1763 = 2098.695 feet

x = AC - AD = 2098.695 - 1740.357 = 358 feet

5 0
2 years ago
The information below represents the cost of Cody's home ownership. What is his average monthly expenditure related to his home?
azamat
Let's calculate all expenses per month

a) Mortgage $1,255 →→→→→→→→→ =  $1,255 per month
b)Taxes $2,881 per year →→  $2,881/12 = $240.083  per month
c) insurance $156 →→→→→→→→→→  =$156 per month 
d) HOA fees $320 per year→→→=$320/12 = $ 26.66 per month 
e)utilities $475→→→→→→→→→→→→→=$475

Average monthly expenditure: a) + b) + c) + d) = $2,152.75 

4 0
2 years ago
Read 2 more answers
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