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2 years ago

If m angle BGF=152 degrees, what is m angle AGF

Mathematics

2 answers:

PtichkaEL [24]2 years ago

8 0

Answer:

A, #1, uno, first one

Step-by-step explanation:

Allushta [10]2 years ago

4 0

The Answer is: 64 degrees

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The point (−3,15) undergoes a translation of 9 units right and 10

Artyom0805 [142]

Answer:

6, 5

Step-by-step explanation:

-3 + 9 = 6

15-10 = 5

6 0

2 years ago

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Find the volume of a right circular cone that has a height of 12.7 m and a base with a circumference of 18.9 m. Round your answe

DochEvi [55]

Step-by-step explanation:

We have,

Height of cone, h = 12.7 m

Circumference of base, C = 18.9 m

The base of a circular cone is circular. The circumference of circle is given by :

$C=2\pi r$

r is radius

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{18.9 }{2\pi}\\\\r=3\ m$

The volume of a right circular cone is given by the formula as :

$V=\dfrac{1}{3}\pi r^2h$

$V=\dfrac{1}{3}\times 3.14 \times 3^2\times 12.7\\\\V=119.634\ m^3$

7 0

2 years ago

Set up a double integral for calculating the flux of the vector field F⃗ (x,y,z)=xi⃗ +yj⃗ through the open-ended circular cylind

katrin [286]

Parameterize the cylinder (call it $S$ ) by

$\vec s(\theta,z)=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath+z\,\vec k$

with $0\le\theta\le2\pi$ and $0\le z\le9$ . Then

$\vec F(x(\theta,z),y(\theta,z),z(\theta,z))=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath$

Take the normal vector to $S$ to be

$\vec s_\theta\times\vec s_z=\sqrt8\cos\theta\,\vec\imath+\sqrt8\sin\theta\,\vec\jmath$

Then the flux of $\vec F$ across $S$ is

$\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(\theta,z),y(\theta,z),z(\theta,z))\cdot(\vec s_\theta\times\vec s_z)\,\mathrm dz\,\mathrm d\theta$

$=\displaystyle\int_0^{2\pi}\int_0^98(\cos^2\theta+\sin^2\theta)\,\mathrm dz\,\mathrm d\theta=\boxed{144\pi}$

7 0

2 years ago

Mario has a business selling muffins. Let x be the price of a muffin. Then, the profit P for Mario’s business is given by p(x)=-

Rufina [12.5K]

To make a positive profit p(x)>0 we need to make:
$-100 x^{2} +350x-150 \ \textgreater \ 0$

Now we solve this for x:
$-2 x^{2} +7x-3 \ \textgreater \ 0$

We have:
a = -2
b = 7
c = -3

We will use formula for quadratic equation:
$x_{1} = \frac{-b+ \sqrt{ b^{2}-4ac } }{2a} \\ \\ x_{2} = \frac{-b- \sqrt{ b^{2}-4ac } }{2a} \\ \\ x_{1} = \frac{-7+ \sqrt{ 49-24 } }{-4} = \frac{-7+5 }{-4} = \frac{-2 }{-4} = \frac{1}{2} \\ \\ x_{2} = \frac{-7- \sqrt{ 49-24 } }{-4} = \frac{-7-5 }{-4} = \frac{-12 }{-4} = 3$

We got two solutions. One is fraction other is whole number. We will not consider fraction because the amount of muffins sold must be whole number. So our solution is:
x>3

5 0

2 years ago

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Heidi solved the equation 3(x + 4) + 2 = 2 + 5(x – 4). Her steps are below: 3x + 12 + 2 = 2 + 5x – 20 3x + 14 = 5x – 18 14 = 2x

saveliy_v [14]

step 1: distributive property.

step 2: combine like terms.

step 3: subtraction property of equality.

step 4: addition property of equality.

step 5: division property of equality.

hope this helps.

3 0

2 years ago

Read 2 more answers