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jok3333 [9.3K]
1 year ago
15

Find the principal amount invested if the amount in a monthly compounded account with a 5.1% interest rate is $9,996.32 after 54

months.
Mathematics
1 answer:
slavikrds [6]1 year ago
4 0
Again, there are 12 months in a year, so 54 months is 54/12 years

\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$9996\\
P=\textit{original amount deposited}\\
r=rate\to 5.1\%\to \frac{5.1}{100}\to &0.051\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to \frac{54}{12}\to &\frac{9}{2}
\end{cases}

\bf 9996=P\left(1+\frac{0.051}{12}\right)^{12\cdot \frac{9}{2}}\implies \cfrac{9996}{\left(1+\frac{0.051}{12}\right)^{12\cdot \frac{9}{2}}}=P
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Step-by-step explanation:

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The College Board SAT college entrance exam consists of three parts: math, writing and critical reading (The World Almanac 2012)
Eddi Din [679]

Answer:

Step-by-step explanation:

Hello!

You have the math and writing SAT scores of twelve students.

There are two variables of interest X₁: Math SAT score of a student. and X₂: Writing the SAT score of a student.

These two variables aren't independent since both of them represent data corresponding to the same student, meaning, that the math and writing scores belong to the same students and not to two separate groups of students.

This is an example of paired samples, to make the statistical test you have to establish a third variable, this variable will be the difference between the other two:

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The parameter of interest is μd is the population mean of the difference between the math and writing SAT scores of the students.

The hypotheses are:

H₀: μd=0

H₁: μd≠0

α: 0.05

The test statistic is a t-student for dependent samples and it's rejection region is two-tailed.

t= \frac{Xd[bar]-Mud}{Sd/\sqrt{n} } = \frac{25-0}{37.05/\sqrt{12} } = 2.33

What is the p-value? Round your answer to four decimal places.

The p-value for this test is: 0.0394

The p-value is less than the level of significance, the decision is to reject the null hypothesis.

b. What is the point estimate of the difference between the mean scores for the two tests?

The sample mean for the variable "difference" is X[bar]d

You can calculate the point estimate of the sample mean of the variable Xd using two ways.

1) You calculate all the differences between the pairs of scores, add them and divide them by the sample size

X[bar]d= ∑di/n

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2) You can calculate the sample mean for each variable and then calculate the difference between the two sample means

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∑X₁= 6168

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X[bar]₂= ∑X₂/n

∑X₂= 5868

X[bar]₂= 5868/12= 489

X[bar]d= X[bar]₁-X[bar]₂ = 514 - 489= 25

What are the estimates of the population mean scores for the two tests?

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Writing test X[bar]₂= 489

Which test reports the higher mean score?

The Math test reports a higher mean score.

I hope it helps!

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mr Goodwill [35]
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Work Shown:

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