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klio [65]
2 years ago
8

he following data set shows the number of dogs counted in a local park each Saturday for 4 months. 33, 36, 31, 37, 37, 38, 31, 3

7, 35, 31, 38, 32, 36, 33, 38 Which dot plot best respresents this data?

Mathematics
2 answers:
lana66690 [7]2 years ago
7 0

General Idea:

To create a dot plot for a set of data we should list the data from lowest to greatest number. Then create a number line which covers all the numbers given in the data. We need to plot number of circles one above as many times based on the frequency of the data.

Applying the concept:

33, 36, 31, 37, 37, 38, 31, 37, 35, 31, 38, 32, 36, 33, 38

Listing the data in ascending order we get

31, 31, 31, 32, 33, 33, 35, 36, 36, 37, 37, 37, 38, 38, 38

We need to plot <u>three </u>circles above 31, <u>one</u> circle above 32, <u>two</u> circles above 33, <u>one</u> above 35, <u>two </u>above 36, <u>three </u>above 37, and <u>three</u> above 38.

Conclusion:

Out of the four options, the <u>correct option is B </u>because that is the only dot plot representing the given set of data.

Luden [163]2 years ago
3 0

Answer:

B

Step-by-step explanation: I took the test

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algol13

Step-by-step explanation:

1.\sum_{i=1}^{5}3i

The simplest method is "brute force".  Calculate each term and add them up.

∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)

∑ = 3 + 6 + 9 + 12 + 15

∑ = 45

2.\sum_{k=1}^{4}(2k)^{2}

∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²

∑ = 4 + 16 + 36 + 64

∑ = 120

3.\sum_{k=3}^{6}(2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

∑ = -4 + -2 + 0 + 2

∑ = -4

4. 1 + 1/4 + 1/16 + 1/64 + 1/256

This is a geometric sequence where the first term is 1 and the common ratio is 1/4.  The nth term is:

a = 1 (1/4)ⁿ⁻¹

So the series is:

\sum_{j=1}^{7}(\frac{1}{4})^{j-1}

5. -5 + -1 + 3 + 7 + 11

This is an arithmetic sequence where the first term is -5 and the common difference is 4.  The nth term is:

a = -5 + 4(n−1)

a = -5 + 4n − 4

a = 4n − 9

So the series is:

\sum_{j=1}^{5}(4j-9)

5 0
2 years ago
The diameters of aluminum alloy rods produced on an extrusion machine are known to have a standard deviation of 0.0001 in. A ran
Ganezh [65]

Answer:

a) Hypothesis mean differs from 0.5025. Rejected

b) P-value = 0

c) 0.50456 < u < 0.50464

Step-by-step explanation:

Given:

- The standard deviation s.d = 0.0001 in

- The mean of the sample x = 0.5046 in

- Sample size n = 25

Find:

a) Test the hypothesis that mean rod. Assume two-sided alternative and significance level of 0.05.

b) Find the p-value for test in part

c) Construct a 95% two-sided confidence interval on the mean rod diameter.

Solution:

- The random variable X: the measurements for rod diameter follows a normal distribution:  

                                       X~ N( 0.5025 , 0.0001 )

- Testing H_o: u_o = 0.5025  , H_1 : u_o not equal 0.5025

- Compute the corresponding Z-score:

                             Z_o = (0.5046 - 0.5025) / 0.0001/sqrt(25)

                             Z_o = 105

- The Z score value with respect to significance level is:

                            Z_a/2 = Z_0.025 = 1.96

Hence, Z_o > Z_a/n

- The hypothesis H_o is rejected the mean differs from 0.5025.

- The corresponding P-Value is:

                            P-value = 2*(1 - sig(Z_o)) = 2*(1 - sig(105))

                           P-value = 2*(1-1) = 0

- The confidence interval is:

                 ( x - Z_a/2(s.d/sqrt(n)) < u <  ( x + Z_a/2(s.d/sqrt(n))

  ( 0.5046 - 1.96(0.0001/sqrt(25)) < u <  ( 0.5046 + 1.96(0.0001/sqrt(25))  

                              0.50456 < u < 0.50464

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2 years ago
Name three common measurements that are expressed as a ratio of two units.
True [87]
Mpg is one...........
8 0
2 years ago
The product of 10 and the difference of a number x and 14 is 90
Ostrovityanka [42]
Write in numbers not words

3 0
1 year ago
A little girl is watching planes take off of the runway from a building's rooftop 40 meters away from the airport. If the height
worty [1.4K]

Answer:

h = 417.81 meters

The altitude of the plane is 417.81 meters

Step-by-step explanation:

given;

The initial height of the girl h0 = 400 m

Horizontal distance from the airport d = 40 m

Angle of elevation of the plane ∅= 24°

The altitude of the plane when the picture was taken is equal to initial height of the girl plus the elevation height.

h = he + h0

And he (elevation height) can be derived as;

he = dtan∅

he = 40tan24°

Substituting into the equation;

h = 40tan24° + 400

h = 417.81 meters

The altitude of the plane is 417.81 meters

5 0
1 year ago
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