If we let x as candy A
y as candy B
a as dark chocolate in candy a
b as dark chocolate in candy b
c as caramel
d as walnut
P as profit
we have the equations:
a + c = x
2b + d = y
a + 2b ≤ 360
c ≤ 430
d ≤ 210
P = 285x + 260y
This is an optimization problem which involves linear programming. It can be solved by graphical method or by algebraic solution.
P = 285(a + c) + 260(2b +d)
If we assume a = b
Then a = 120, 2b = 240
P = 285(120 + 120) + 260(240 + 120)
P = 162000
candy A should be = 240
candy B should be = 360
Answer:
C) 31.2
Step-by-step explanation:
The length of AB can be found from the Pythagorean theorem:
AB² = AD² +BD²
AB = √(25 +144) = 13
All of the right triangles are similar, so ...
BC/BD = AB/AD
BC = BD(AB/AD) = 12(13/5)
BC = 31.2 . . . units
Answer:
- B. On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.
Step-by-step explanation:
<u>Graph of the function:</u>
The domain is x ≥ 0, the range y ≤ 1
Correct answer choice is B
- On a coordinate plane, an absolute value curve curves up and to the right in quadrant 4 and starts at y = 1.
<em>The graph is attached</em>
Answer:
x=
2.6
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
3 − √11
Step-by-step explanation:
For polynomials with rational coefficients, any radical roots must come in conjugate pairs. To find the conjugate, simply reverse the sign of the radical.
