Answer:
R = (- 3.5, - 7 )
Step-by-step explanation:
Using the Section formula
=
=
=
= - 3.5
=
=
=
= - 7
Thus coordinates of R = (- 3.5, - 7 )
Jack bought a car for $17,500. The car loses $750 in value each year. Which equation represents the situation? Question 9 option
2 answers:
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Answer:
AB = √18 , BC=√18 and CA =4
AB²+BC² = CA² and AB=BC
ΔABC isosceles right angled triangle.
Step-by-step explanation:
Given vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k
A( 0,7,10), B( -1,6,6) C(-4,9,6)
AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k
AB =
BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j
BC=
CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k
CA =
Since AB²+BC² = CA²
And AB=BC
Therefore it follows that ΔABC is a right angled isosceles triangle
The rest of the queastion is :
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>
we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span>
= 5
</span>LM = <span>
= 3
KM = </span><span>
= 4
now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)
check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span>
= 5
</span>L'M' = <span>
= 3
K'M' = </span><span>
= 4</span></span>
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>
<span>The distance
between two points (x₁,y₁),(x₂,y₂) = d
</span>
we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span>
</span>LM = <span>
KM = </span><span>
now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)
check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span>
</span>L'M' = <span>
K'M' = </span><span>