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Gnoma [55]
2 years ago
12

The coordinate values of the vertices of △klm are integers. triangle klm has vertices located at (1, 1), (5, 4) and (5, 1). whic

h set of coordinate pairs could represent the vertices of a triangle congruent to △klm?
Mathematics
1 answer:
worty [1.4K]2 years ago
6 0
The rest of the queastion is :
<span> A) (-1, 1), (-1, 4), (2, 1)
B) (0, 0), (3, 4), (0, 5)
C) (-1, 1), (-4, 5), (-1, 5)
D) (0, 0), (-5, 0), (0, 4)
==============================
</span>

<span>The distance between two points (x₁,y₁),(x₂,y₂) = d
d = \sqrt{ (x2-x1)^{2} + (y2-y1)^{2} }</span>


we have <span>K(1, 1), L(5, 4) and M(5, 1)
we will find the length between each two points.
KL = </span><span>d = \sqrt{ (5-1)^{2} + (4-1)^{2} } = 5
</span>LM = <span>d = \sqrt{ (5-5)^{2} + (1-4)^{2} } = 3
KM = </span><span>d = \sqrt{ (5-1)^{2} + (1-1)^{2} } = 4

now check each group from the choices
the group that will give the same result will be the correct choice.
</span>The correct choice is C
<span>C) (-1, 1), (-4, 5), (-1, 5)

check the answer;
</span><span>K'(-1, 1), L'(-4, 5), M'(-1, 5)
</span>
<span>K'L' = <span>d = \sqrt{ (-4+1)^{2} + (5-1)^{2} } = 5
</span>L'M' = <span>d = \sqrt{ (-1+4)^{2} + (5-5)^{2} } = 3
K'M' = </span><span>d = \sqrt{ (-1+1)^{2} + (5-1)^{2} } = 4</span></span>
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