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Inga [223]
2 years ago
9

a group of 10 people ran an average of 2.7 miles in one week. if the first 4 people in the group averaged 3 miles, what did the

last 6 people average
Mathematics
1 answer:
FromTheMoon [43]2 years ago
4 0
In this question, 10 people average running distance is 2.7miles. Then the sum of their running distance would be: 10 people * 2.7 miles/people= 27 miles.

The group then divided into 2, 4 people with 3 miles average and 6 people with unknown average. Since the people are same like the 10 people group, their total running distance would be the same. The calculation would be:

total distance = group1 * average1 + group2 * average2
27 miles= 4 people * 3 miles/people + 6 people* average2
6 people * average2 = 27 miles -12 miles = 15 miles
average2= 15 miles/6people= 2.5 miles/people
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Amiraneli [1.4K]

Given

There are four defenders on a soccer team

if this represents 20 percent of the players on the team

Find out the total number of players on the team.

To proof

As given in question

four defenders on a soccer team

this represents 20 percent of the players on the team

let the total number of players = x

First convert 20% in the decimal form

\frac{20}{100} =0.20

Than the equation becomes

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2 years ago
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Answer:

Let 'x' and 'y' be two different numbers.

Leila says that 75% of a number will always be greater than 50% of a number. The inequality that represents this statement is the following:

0.75x > 0.5y

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200 students attend a school which offers French and History. 10% of those who take History also take French and 4 times as many
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Answer:   P(hist& french)=16/200=0.08

Step-by-step explanation:

To find the required probability we have to know what is the number of students that take both History and French ( Intersection of 2 circles in Venn diagram)

1. Lets find the number of students that take History or French or both.

We know that 8% from 200 take neither History or French. So number or students who take History or French or both is 200-200*0.08=184

2. Let number of students that takes French (or both Fr+Hist)=x (left circle)

So number of students that takes History (or both Fr+Hist)=4x (right circle)

So number of students that take both French+History= 10% from 4x or

0.1*4x=0.4x (circles'  intersection)

3. Now we have the equation as follows:

x+4*x-0.4*x = 184

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x=40 students takes French (or both French+ History)

4*x= 40*4=160 students takes History (or both French+ History)

10% from 160 =0.1*160=16 students takes both History and French

P(hist& french)=16/200=0.08

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