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Masteriza [31]
2 years ago
13

Joy makes 6.5 litres of soup, correct to the nearest 0.5 litre. She serves the soup in 280 ml portions, correct to the nearest 1

0ml. 22 people order this soup. Does Joy have enough soup
Mathematics
2 answers:
max2010maxim [7]2 years ago
8 0

Amount of soup made by Joy = 6.5 liters and nearest to 0.5 liters is 7 liters

Amount of soup in each serving portion = 280 ml. As the last digit is zero, this will not be rounded off and nearest value will remain 280

Number of people being served = 22

So total consumption of soup for 22 people is =

22\times280=6160 = 6160 ml

In liters this is = \frac{6160}{1000}=6.160 liters

Hence, Joy has enough soup for 22 people.

Levart [38]2 years ago
7 0

Answer:

Joy definitely does have enough soup for 22 people.


Step-by-step explanation:

Upper Bound: 285ml  turn it to 0.285 L                      10÷2=5

280ml  :

Lower Bound: 275ml turn it  to 0.275 L

Upper Bound: 6.75 L                           0.5÷2=0.25

6.5 Litters  :

Lower Bound:6.25  L

6.75÷0.275=24.54 or 25  

6.25÷0.285=21.92 or 22

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Which of the following gives all of the sets that contain -1/2?
fiasKO [112]
ANSWER


The set of all rational numbers and the set of all real numbers.


EXPLANATION

The set of rational numbers contains all numbers that can be written in the form,


\frac{a}{b}


where a and b are integers and b≠0.


The given number is

-  \frac{1}{2}


It belongs to the set of rational numbers.


The set of rational numbers is a subset of the set of real numbers.

Hence

-  \frac{1}{2}
also belongs to the set of real numbers.


The correct answer is A.
3 0
2 years ago
Suppose that 20% of the adult women in the United States dye or highlight their hair. We would like to know the probability that
Rasek [7]

Answer:

71.08% probability that pˆ takes a value between 0.17 and 0.23.

Step-by-step explanation:

We use the binomial approxiation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.2, n = 200. So

\mu = E(X) = np = 200*0.2 = 40

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{200*0.2*0.8} = 5.66

In other words, find probability that pˆ takes a value between 0.17 and 0.23.

This probability is the pvalue of Z when X = 200*0.23 = 46 subtracted by the pvalue of Z when X = 200*0.17 = 34. So

X = 46

Z = \frac{X - \mu}{\sigma}

Z = \frac{46 - 40}{5.66}

Z = 1.06

Z = 1.06 has a pvalue of 0.8554

X = 34

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 40}{5.66}

Z = -1.06

Z = -1.06 has a pvalue of 0.1446

0.8554 - 0.1446 = 0.7108

71.08% probability that pˆ takes a value between 0.17 and 0.23.

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Answer:

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Step-by-step explanation:

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andreyandreev [35.5K]

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Step-by-step explanation:

I did it

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