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aniked [119]
2 years ago
11

Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e

stimate? Explain.
Mathematics
2 answers:
Jet001 [13]2 years ago
7 0
He rounded 336 to 340 and 287 to 290. Then he subtracted 290 from 340, that's how he got 50.
malfutka [58]2 years ago
3 0

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

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nikklg [1K]
There are a couple of ways you can solve this. You can write it out like
(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)(K-3)
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Or you can use the binomial theorem (google it if you dont know)
The solution should be:
(K^7) - 21(k^6) + 189(k^5) - 945(k^4) + 2835(k^3) - 5103(k^2) + 5103k - 2187
3 0
2 years ago
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Assume the blood pressures of 10 people were measured before and after sleeping for the night. What is the corresponding critica
NeX [460]

Answer:

For the critical value we need to calculate the degrees of freedom given by:

df = n-1= 10-1=9

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

|t_{crit}| =1.833

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value with right arm , y = test value with left arm  

The system of hypothesis for this case are:  

Null hypothesis: \mu_y- \mu_x = 0  

Alternative hypothesis: \mu_y -\mu_x \neq 0  

The first step is calculate the difference d_i=y_i-x_i

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= \frac{361}{5}  

The third step would be calculate the standard deviation for the differences, and we got:  

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}  

The 4 step is calculate the statistic given by :  

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}  

For the critical value we need to calculate the degrees of freedom given by:

df = n-1= 10-1=9

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

|t_{crit}| =1.833

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2 years ago
Alison wants to distribute the carnations and roses equally among the 6 flower shops. Factor the expression from Part A using 6
mixer [17]

Answer:

6

Step-by-step explanation:

3 0
2 years ago
If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?
Volgvan

Answer:

The domain of the function (cd)(x) will be all real values of x except x = 2.

Step-by-step explanation:

The two functions are c(x) = \frac{5}{x - 2} and d(x) = x + 3

So, (cd)(x) = (\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}

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8 0
2 years ago
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The system on the left can be reduced to: t + u = 9 9t – 9u = –9 Solving the system t= , u=
LenaWriter [7]
We have that
<span>t + u = 9 --------> t=9-u-----------> equation 1
9t – 9u = –9----------> equation 2
</span>
I substitute 1 in 2
9*[9-u]-9u=-9
81-9u-9u=-9
18u=81+9
18u=90
u=90/18---------> u=5
t=9-u------> t=9-5----> t=4

the answer is
u=5
t=4




5 0
2 years ago
Read 2 more answers
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