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2 years ago

5

Kayla is going to Japan for vacation. She will exchange $300 for Japanese yen. The exchange rate is $1=85.74 yen. How many yen w

ill Kayla receive?

2 answers:

Nezavi [6.7K]2 years ago

7 0

Answer:

25,722 yen

Step-by-step explanation:

300x85.74 is the simplest way to do this and I am just adding words to compete this

Stels [109]2 years ago

3 0

Answer:

85.74 x 300 $ = 25722 Yem

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9 out of 10 people at a game are rooting for the home team. What is the probability that exactly 6 of 8 people sitting together

scZoUnD [109]

A random supporter roots the home team with probability 0.9, and the away team with probability 0.1.

Choosing 6 out of 8 supporters who root for the home team has probability

$\displaystyle\binom{8}{6}\cdot 0.9^6\cdot 0.1^2 = 28\cdot0.531441\cdot 0.01=0.14$

7 0

2 years ago

The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c

boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

$p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!}$ for x = 0, 1, 2, ...

where $\lambda$ , the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is $1.2 \cdot 3 =3.6$

The probability of exactly three flaws in 150 m of cable is

$P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246$

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is $1.2 \cdot 2 =2.4$

$P(X\geq 2)=1-P(X$

$P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155$

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

$P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143$

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

$(0.36143)(0.36143) = 0.13063$

4 0

2 years ago

A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.

qwelly [4]

A = 0.9 o
<span>so, </span>
<span>o = a/0.9 = 1.111a </span>
<span>so, the orange is 11% heavier than the apple.

glad i could help(:</span>

6 0

2 years ago

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Determine the product: (46.2 × 10–1) ⋅ (5.7 × 10–6). Write your answer in scientific notation.

lianna [129]

Answer:

A

Step-by-step explanation:

10-6 X 10-1 = 10-7

5.7*46.2=263.34

263.34=2.6334 x 10^2

10^2 x 10^-7 = 10^-5

so

=2.6334 x 10-5

7 0

1 year ago

Vadim26 [7]

Answer:

Her answer is wrong because she the object cannot hit the ground at negative seconds. She could’ve have used other methods because she used the quadratic formula. The advantages is that it works for every situation. The disadvantages is that it takes longer. She should’ve used a different method.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers