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1 year ago

Solve for m: -3(1 – 5m) = — 38 + 8m

Mathematics

2 answers:

sashaice [31]1 year ago

6 0

Answer:

-5

Step-by-step explanation:

Solnce55 [7]1 year ago

3 0

Answer:

m = - 5

Step-by-step Explanation:

$-3(1-5m)=-38+8m \\ \\ - 3 + 15m = - 38 + 8m \\ \\ 15m - 8m = 3 - 38 \\ \\ 7m = - 35 \\ \\ m = \frac{ - 35}{7} \\ \\ \huge \purple{ \boxed{m = - 5}}$

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Isla flipped a coin 30 times. The coin landed heads up 9 times and tails up 21 times.

Debora [2.8K]

Answer:

both are equal

Step-by-step explanation:

there are two side tails and heads so there a 1/2 chance it will land on heads

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1 year ago

Express Rs 1.50 as a percentage of 200 cents

Juli2301 [7.4K]

1 $ = 100 cents

1.5 $ = 150 cents

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1 year ago

A stadium has two sponsorship deals. Deal A had revenue of $100,000 and expense of $10,000. Deal B has revenue of $50,000 and ex

horsena [70]

Answer:

Deal A) 90% Profit ; Deal B) 60% Profit

Step-by-step explanation:

Multiple ways of solving this problem here is one way:

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The same is true for the other equation:

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1 year ago

Read 2 more answers

The picture below shows a box sliding down a ramp:

Gennadij [26K]

Answer:

$AC=15.1\ ft$

Step-by-step explanation:

we know that

In the right triangle ABC

The function sine of angle 68 degrees is equal to divide the opposite side SB by the hypotenuse AC

$sin(68\°)=\frac{AB}{AC}$

substitute the values and solve for AC

$sin(68\°)=\frac{14}{AC}$

$AC=\frac{14}{sin(68\°)}$

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1 year ago

Given directed line segment QS , find the coordinates of R

Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

If point Q is at ( $x_1,y_1$ ) and S at ( $x_2,y_2$ ) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

$x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1$

Let us assume Q(−9,4) and S(7,−4)

$x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1$

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2 years ago