Answer:
Step-by-step explanation:
Rate of leakage, R(t) = 1400 e^0.06t gallons/h
fraction remains , S(t) = e^(-0.32t)
initial contaminant = 1000 gallon
gallons contaminant present after t hour is S(t) R(t)
G(t) = S(t) R(t)
Put t = 18 hours
Taking log on both the sides
ln G = ln 1400 - 0.26 x 18
ln G = 7.244 - 4.68
ln G = 2.564
G = 13 gallons
Answer:
No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that true average task time with armor is less than 2 seconds.
Then, the null and alternative hypothesis are:
The significance level is 0.01.
The sample has a size n=52.
The sample mean is M=1.95.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.
The estimated standard error of the mean is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):
As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.
Answer:
There are 250 nails and 150 screws in the bucket.
Step-by-step explanation:
Let Number of nails in bucket be x.
Also Let number of screws in the bucket be y.
Together, there are 400 fasteners in the bucket.
Hence the equation can be framed as;
Also Given:
The number of nails in the bucket is 50 less than twice a number of screws.
Hence the equation can be framed as;
Substituting the value of x in equation 1 we get;
Now we have value of y we will substitute in equation 1 we get;
Hence there are 250 nails and 150 screws in the bucket.