All categories

2 years ago

Which term in the arithmetic sequence 11, 4,-3 . . . is -129?

Mathematics

1 answer:

telo118 [61]2 years ago

4 0

Answer:

23rd term

Step-by-step explanation:

Plz mark as Brainliest!

You might be interested in

Explain why the vertical line test is used to determine if a graph represents a function.

Aleksandr [31]

Hi there Mary Dominguez, So what a vertical line test down is to find out if a particular graph is a function or not. What you do is take a vertical strait line and move it right to left or left to right, depending on your preference, along the X axis. The reason this works is a function can not have an x that has 2 different y values. If we use the vertical line test on a graph with say a graph that has (2,3) and (2,4) we can use the vertical line test and see that the line hits 2 points at once which means its not a function :)

4 0

2 years ago

Read 2 more answers

Willis bought a gallon of paint. He painted a wall that is 9 ft high and 10 ft wide. Then he used the rest of the paint to paint

GalinKa [24]

Well 9×10 is 90, 90+46 is 136. the paint covered 136 square feet

4 0

2 years ago

Read 2 more answers

What is the simplified base of the function f(x) = One-fourth (Root Index 3 StartRoot 108 EndRoot) Superscript x?

son4ous [18]

Answer:

Simplified base would be 3∛4

Step-by-step explanation:

Given exponential function,

$f(x)=\frac{1}{4}(\sqrt[3]{108})^x$

Since, in an exponential function $f(x)=ab^x$

b is called base.

∵ 108 = 2 × 2 × 3 × 3 × 3,

Or 108 = 4 × 3³,

$\implies \sqrt[3]{108} = \sqrt[3]{4\times 3^3}$

$\sqrt[3]{108}=\sqrt[3]{4}\times \sqrt[3](3^3)$ ( Using $\sqrt[n]{ab}=\sqrt[n]{a}\times \sqrt[n]{b}$ )

$\sqrt[3]{108}=\sqrt[3]{4}\times (3^3)^\frac{1}{3}$

$\sqrt[3]{108}=\sqrt[3]{4}\times 3^{3\times \frac{1}{3}}$ ( Using power of power property of exponent )

$\sqrt[3]{108}=3\sqrt[3]{4}$

Hence, the required simplified base would be 3∛4

i.e. SECOND option is correct.

8 0

2 years ago

Read 2 more answers

A circle is shown. Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W.

Marat540 [252]

Given:

Secants S V and T V intersect at point V outside of the circle. Secant S V intersects the circle at point W. Secant T V intersects the circle at point U.

The length of TU is (y - 2).

The length of UV is 8.

The length of SW is (y + 4)

The length of WV is 6.

We need to determine the length of line segment SV.

Value of y:

The value of y can be determined using the intersecting secant theorem.

Applying, the theorem, we get;

$WV \times SV=UV \times TV$

Substituting the values, we have;

$6 \times (y+4+6)=8 \times (y-2+8)$

$6 \times (y+10)=8 \times (y+6)$

$6y+60=8y+48$

$-2y+60=48$

$-2y=-12$

$y=6$

Thus, the value of y is 6.

Length of SV:

The length of SV is given by

$SV=SW+WV$

$SV=y+4+6$

$SV=6+4+6$

$SV=16$

Thus, the length of SV is 16 units.

Hence, Option D is the correct answer.

7 0

2 years ago

Read 2 more answers

John and Rebecca are making flags. They can choose from 4 background colors: Blue, Red, Yellow, and Orange. On top of that they

klio [65]

There are 4 base colors, and 3 top colors.
Blue and teal
blue and green
blue and white

red and teal
red and green
red and white

yellow and teal
yellow and green
yellow and white

orange and teal
orange and green
orange and white

they can make a total of 12 different flags.

8 0

2 years ago

Which term in the arithmetic sequence 11, 4,-3 . . . is -129?​

Which term in the arithmetic sequence 11, 4,-3 . . . is -129?