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zimovet [89]
2 years ago
11

Find the missing term in the following sequence ? 1, 4, 11, 26, 57, 120, ______

Mathematics
2 answers:
Advocard [28]2 years ago
7 0

Given sequence;

1, 4, 11, 26, 57, 120, _

The missing term  =?

Solution;

We need to find the relationship between each term and then we can find the missing term;

      1, 4, 11, 26, 57, 120, _ ;

 let us start with the first two;

       3 x 2 + 1  = 7 + 4  = 11

       7 x 2 + 1  =  15 + 11 = 26

       15 x 2 + 1 = 31 + 26 = 57

       31 x 2 + 1 = 63 + 57 = 120

       63 x 2 + 1 = 127  + 120 = 247

   

        We see this pattern and can conclude that the missing term is 247

Marysya12 [62]2 years ago
5 0

Answer:

247

Step-by-step explanation:

1,4,11,26,57,120. see the pattern that emerges from the series:

4–1 = 3; 3–1 = 2 = 2^1

11–4 = 7; 7 - 3 = 4 = 2^2

26 - 11 = 15; 15 - 7 = 8 = 2^3

57 - 26 = 31; 31 - 15 = 16 = 2^4

120 - 57 = 63; 63 - 31 = 32 = 2^5

so the next number should be 64+63 = 127+120 = 247.

check: 247–120 = 127; 127–63 = 64 = 2^6. correct.

so the next number is 247. 2^n+(n-1)

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If an intravenous solution containing 123 mg of a drug substance in each 250-mL bottle is to be administered at the rate of 200
12345 [234]

Answer:

24.39mL of the solution would be given per hour.

Step-by-step explanation:

This problem can be solved by direct rule of three, in which there are a direct relationship between the measures, which means that the rule of three is a cross multiplication.

The first step to solve this problem is to see how many mg of the solution is administered per hour.

Each minute, 200 ug are administered. 1mg has 1000ug, so

1mg - 1000 ug

xmg - 200 ug

1000x = 200

x = \frac{200}{1000}

x = 0.2mg

In each minute, 0.2 mg are administered. Each hour has 60 minutes. How many mg are administered in 60 minutes?

1 minute - 0.2 mg

60 minutes - x mg

x = 60*0.2

x = 12mg

In an hour, 12 mg of the drug is administered. In 250 mL, there is 123 mg of the drug. How many ml are there in 12 mg of the drug.

123mg - 250mL

12 mg - xmL

123x = 250*12

x = \frac{250*12}{123}

x = 24.39mL

24.39mL of the solution would be given per hour.

7 0
1 year ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
1 year ago
Read 2 more answers
What is the result of anding 255 and 15?
Tema [17]
The result of adding 255 and 15 is;

255 + 15 = 270


8 0
1 year ago
Compare the functions shown below: f(x) = 4x + 5 g(x) tangent function with y intercept at 0, 2 h(x) = 3 sin(2x + π) − 2 Which f
KATRIN_1 [288]
The y-intercept of the graph of a function is the value of f(0) for any function f.
That is, it is the y-value in the pair (0, y)



The y-intercept of <span>f(x) = 4x + 5 is f(0)=4*0+5=5

The y-intercept of (0, 2) is 2.

The y-intercept of </span>h(x) = 3 sin(2x + π) − 2 is:

h(0) = 3 sin(2*0 + π) − 2=3 sin(π) − 2=3*0-2=-2


<span>Answer: The function f has the greatest y-intercept.


</span>
7 0
2 years ago
John Anderson bought a home with a 10.5% adjustable rate mortgage for 30 years. He paid $9.99 monthly per thousand on his origin
aliina [53]
Old
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=549.45
New
10.68×55
=587.4

((10.68÷9.99)−1)×100
=6.9%
6 0
1 year ago
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