Jack's average in math for the first nine week was an 88. His second nine weeks average decreased 12.5 . What was his average fo
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Answer:
4. A)
3. A)
2. D)
1. C)
Step-by-step explanation:
4. Two families combined have <em>at</em><em> </em><em>least</em><em> </em>3 pets.
3. $1500 is your result, so everything else is straightforward simple, knowing that the keywords <em>at</em><em> </em><em>least</em><em> </em>$1500<em> </em>mean <em>greater</em><em> </em><em>than</em><em> </em><em>or</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em>$1500.
2. Find the correspondents, then determine what inequality to use. In this case, you will use <em>less than</em><em> </em><em>or equal</em><em> </em><em>to</em><em> </em>because overpaying is UNNECESSARY.
1. <em>Eight</em><em> </em><em>dollars</em><em> </em><em>each</em><em> </em><em>pizza</em><em> </em>and <em>twelve</em><em> </em><em>dollars</em><em> </em><em>each</em><em> </em><em>pizza</em><em> </em>is <em>12x</em><em> </em>and <em>8x</em>.<em> </em>The rest is straightforward simple because you now have your <em>initial</em><em> </em><em>costs</em><em> </em>of <em>$</em><em>45</em><em> </em>and <em>$</em><em>5</em>,<em> </em>and the exercise tells you that the total charge for Company A is <em>less than</em> the total charge for Company B, therefore you have your answer.
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Answer:
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Step-by-step explanation:
Part A
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set in four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
Interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
Interquartile range of the data is
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.
When the occurrence of one event say A does not affect the occurrence of another event say B, than the two events are said to be independent such that;
where, P(A) = probability of occurrence of event A
and P(B) = probability of occurrence of event B
(a).
Now, let event A = Sarah scores more than 175
and event B = Thomas scores more than 175
Thus, P(A)= Probability that Sarah scores more than 175 = 0.4
and P(B)= Probability that Thomas scores more than 175 = 0.2
Since, the scores are independent, thus the probability that both Sarah and Thomas scores more than 175 is,
Hence, the required probability is 0.08
(b).
When the occurrence of one event say A affects the occurrence of another event say B, than the two events are said to be dependent such that;
Now, let event A = Sarah scores more than 175
and event B = Thomas scores more than 175
Thus, P(A)= Probability that Sarah scores more than 175 = 0.4
P(B)= Probability that Thomas scores more than 175 = 0.2
and P(B|A) = Sarah scores more than Thomas given that Thomas scores more than 175 = 0.3
Thus, the required probability is calculated as follows;