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mezya [45]
2 years ago
10

A horse race has 14 entries and one person owns 5 of those horses. assuming that there are no​ ties, what is the probability tha

t those five horses finish first comma second comma third comma fourth comma and fifth ​(regardless of​ order)
Mathematics
1 answer:
makvit [3.9K]2 years ago
4 0
We know that
<span>entries------------ > 14 in total.
the owner has----------->  5 horses.

if each horse has the same probability of winning, then the probability that the owner's horses will come in first, second, third, fourth </span>and fifth will be as follows: <span>
we have 5 spots. 

the probability that one of those 5 horses will be first is 5/14
the probability that one of the remaining 4 horses will be second is 4/13.
the probability that one of the remaining 3 horses will be third is 3/12.
</span>the probability that one of the remaining 2 horses will be fourth is 2/11.<span>
the probability that the remaining horse will be fifth is 1/10. 

the total probability is [5/14 * 4/13 *3/12 *2/11 *1/10]
(120/240240)=1/2002=0.0004995

the answer is 0.0004995</span>
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A rectangle has an area of 18cm2 (squared). The lengths of the sides are whole numbers. How long could the sides of the rectangl
marishachu [46]

Answer:

9 cm, 2 cm

or

6 cm , 3 cm

Step-by-step explanation:

There are two possibilities of the lengths of the sides of rectangle

18= 9\times 2\\18=6\times 3\\

7 0
2 years ago
What is the value of y?<br> y = <br><br> Find the following angle measures.<br> mJKM = °<br> mMKL
shusha [124]

Answer: ∠JKM = 106\textdegree and

 ∠JKM = 74\textdegree

Step-by-step explanation:

Since we have given that

∠JKM=10y+6

∠MKL=8y-6

Since they are linear pairs ,

So, 10y+6+8y-6=180\textdegree \\\\18y=180\textdegree \\\\y=\frac{180\textdegree}{18\textdegree}\\\\y=10\textdegree

∠JKM = 10\times 10+6=100+6=106\textdegree

and

∠MKL = 8\times 10-6=80-6=74\textdegree

8 0
2 years ago
Read 2 more answers
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

1010010001

0111001110

Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

c) Sub set {2, 3, 4, 7, 8, 9} = 0111001110

5 0
2 years ago
Point M and N are midpoints of AB and DA respectively.
Fed [463]
<span>triangle CDN ≅ triangle CBM
</span><span>
Statement | Reason
line DC ≅ __BC___ | The sides of a square are congruent.
line BM ≅ __DN___ | They are both half the length of a side of the square.
angle __D___ ≅ angle B | All the angles of a square are congruent.
triangle CDN ≅ CBM | 
by
</span><span>SAS</span>
5 0
2 years ago
the size of a rectangular computer screen is determined by the length of its diagonal. tom buys a 52cm screen that is 33 cm high
Snowcat [4.5K]

Answer:

40.20cm approx

Step-by-step explanation:

Step one

given data

We are told that the dimension of a computer screen

diagonal= 52 cm

height= 33cm

Length = ?

Required

The length of the base of the screen

Step two

Let us use Pythagoras theorem to find the length of the base

Hyp^2= Opp^2+ Adj^2

52^2= 33^2+ L^2

2704= 1089+L^2

L^2= 2704-1089

L^2= 1615

L=√1615

L= 40.20cm approx

<u>The length is 40.20cm approx.</u>

8 0
2 years ago
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