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mezya [45]
2 years ago
10

A horse race has 14 entries and one person owns 5 of those horses. assuming that there are no​ ties, what is the probability tha

t those five horses finish first comma second comma third comma fourth comma and fifth ​(regardless of​ order)
Mathematics
1 answer:
makvit [3.9K]2 years ago
4 0
We know that
<span>entries------------ > 14 in total.
the owner has----------->  5 horses.

if each horse has the same probability of winning, then the probability that the owner's horses will come in first, second, third, fourth </span>and fifth will be as follows: <span>
we have 5 spots. 

the probability that one of those 5 horses will be first is 5/14
the probability that one of the remaining 4 horses will be second is 4/13.
the probability that one of the remaining 3 horses will be third is 3/12.
</span>the probability that one of the remaining 2 horses will be fourth is 2/11.<span>
the probability that the remaining horse will be fifth is 1/10. 

the total probability is [5/14 * 4/13 *3/12 *2/11 *1/10]
(120/240240)=1/2002=0.0004995

the answer is 0.0004995</span>
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Sergio039 [100]
Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive

We are given
P(A)=0.75  [ probability that Nathan is allergic ]
P(T|A)=0.98  [probability of testing positive given Nathan is allergic to Penicillin]

We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)

From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735

Hope this helps!!
3 0
2 years ago
Using the power series methods solve the 1st order Lane-Emden Equation:
nikklg [1K]

Answer:

Step-by-step explanation:

xy = 2y + xy = 0

Hence, 2y + xy = 0 ---------(1)

Differentiating equation (1) n times by Leibnitz theorem, gives:

2y(n) + xy(n) + ny(n - 1) = 0

Let x = 0: 2y(n) + ny(n - 1) = 0

2y(n) = -ny(n - 1)

∴ y(n) = -ny(n - 1)/2 for n ≥ 1

For n = 1: y = 0

For n = 2: y(1) = -y

For n = 3: -3y(2)/2

For n = 4: -2y(3)

5 0
2 years ago
La fuerza necesaria para evitar que un auto derrape en una curva varía inversamente al radio de la curva y conjuntamente con el
Vika [28.1K]

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

7 0
2 years ago
Which graph represents a bike traveling at a constant rate of 12 miles per hour
mrs_skeptik [129]
The third graph if I am correct
8 0
2 years ago
Read 2 more answers
The price that a company charged for a basketball hoop is given by the equation 50 - 5x^2 where x is the number of hoops that ar
DiKsa [7]

Answer: The correct option is first, the number of basketball hoops did the company previously produce to make the same profit is 1.3 million hoops.

Explanation:

Let the number of basketball hoops did the company previously produce to make the same profit be x.

Total Revenue = Price * Quantity

The total revenue in million dollars is,

\text{Total Revenue}=(50-5x^2)x

\text{Total Revenue}=50x-5x^3

The total cost in million dollars is,

Total Cost = One unit cost * Quantity

\text{Total Cost}=30x

Profit = Total Revenue - Total Cost

\text{Profit}=50x-5x^3-30x

The profit is 15 million.

15=20x-5x^3

5x^3-20x+15=0\\x^2-4x+3=0\\(x-1)(x^2+x-3)=0

The value of x is 1 and \frac{-1\pm \sqrt{13}}{2}.

The production is always positive therefore the value of x either 1 or 1.3. Since 1 million is not available in the options therefore the the correct optin is 1.3 million hoops.

4 0
2 years ago
Read 2 more answers
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