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2 years ago

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For the 7:30 showtime, 140 movie tickets were sold. Receipts from $13 adult tickets and the $10 senior tickets totaled $1,664. H

ow many adult tickets and how many senior tickets were sold?

1 answer:

aleksandrvk [35]2 years ago

4 0

Answer:

\textrm{\Lambda \aa \gamma \kappa 1256789034\sum \sum \prod \sqrt[{_{}}^{}]{}}

Step-by-step explanation:

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Jessica wants to calculate her grade in her accounting class.she has four test grades (82, 65, 71, and 77) and a homework grade

Aleks04 [339]

To solve the problem, get the percentage of each test by multiplying the score and the percentage then add it all up:

82 * .25 (highest test grade) + 65* .15 (lowest test grade) + 71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework grade)

= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number

3 0

2 years ago

If the shape of our data set is multimodal, we expect:

scoray [572]

Answer: (D) none of the these.

Step-by-step explanation:

A multimodal distribution refers to a distribution with two or more modes.

If the shape of our data set is multimodal, the it will show two or more peaks which represents the number modes in the data.

Since it has no relation with mean or median of the data, there for the correct option will be "none of these".

3 0

2 years ago

What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S

Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

4 0

1 year ago

Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)

MakcuM [25]

Answer:

The cost is $9.70 per kilogram.

Step-by-step explanation:

This can be solved by a rule of three.

In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.

When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too. In this case, the rule of three is a cross multiplication.

When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease. In this case, the rule of three is a line multiplication.

In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

The problem states that cheese costs $4.40 per pound. Each kg has 2.2 pounds. How many kg are there in 1 pound. So:

1 pound - xkg

2.2 pound - 1 kg

$2.2x = 1$

$x = \frac{1}{2.2}$

$x = 0.45$ kg

Since cheese costs $4.40 per pound, and each pound has 0.45kg, cheese costs $4.40 per 0.45kg. How much does is cost for 1kg?

$4.40 - 0.45kg

$x - 1kg

$0.45x = 4.40$

$x = \frac{4.40}{0.45}$

$x = 9.70$

The cost is $9.70 per kilogram.

6 0

2 years ago

Katie has a necklace for $14.5 plus 6% tax. sharon buys a bracelet for $12 plus 6% tax. enter the sum, in dollars, that Katie an

REY [17]

$28.09
Because 6 percent of both of them combined is 1.59
1.59 + 14.5 + 12 = $28.09

5 0

2 years ago

Read 2 more answers