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2 years ago

Given f(x) = 70 + 11x, find x when f(x) =158

Mathematics

1 answer:

Mumz [18]2 years ago

5 0

Answer:

$\huge \boxed{x = 8}$

Step-by-step explanation:

f(x) = 70 + 11x

To find the value of x when f(x) =158 , equate f(x) to 158

We have

$70 + 11x = 158 \\ 11x = 158 - 70 \\ 11x = 88$

Divide both sides by 11

$\frac{11x}{11} = \frac{88}{11} \\$

We have the final answer as

Hope this helps you

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a person on a tour has rupees 12000 for his daily expenses. In order to extend his journey for 2 more days he had to cut down hi

myrzilka [38]

Answer:

Duration of the tour he planned first is 8 days.

Step-by-step explanation:

Given that a person has 12000 rupees for his daily expenses.

Let x be the number of days.

Then daily expenses per day $=\frac{12000}{x}$

Given that number of day is increased by 2 more days, that is number of days is x+2.

New daily expense per day $\frac{12000}{x+2}$

Given that this new daily expenses are 300 less than original.

That is $\frac{12000}{x}-\frac{12000}{x+2}=300$

$\frac{12000(x+2)-12000x}{x(x+2)}=300$

$\frac{24000}{x(x+2)}=300$

$x(x+2)=\frac{24000}{300}$

$x^{2}+2x-80=0$

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x=8 or -10.

Since number of days cannot be negative, duration of the tour planned=8.

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2 years ago

Suppose babies born in a large hospital have a mean weight of 3316 grams, and a standard deviation of 324 grams. If 83 babies ar

Anuta_ua [19.1K]

Answer: 0.129

Step-by-step explanation:

Let $\overline{X}$ denotes a random variable that represents the mean weight of babies born.

Population mean : $\mu= \text{3316 grams,}$

Standard deviation: $\text{324 grams}$

Sample size = 83

Now, the probability that the mean weight of the sample babies would differ from the population mean by greater than 54 grams will be :

$P(|\mu-\overline{X}|>54)=1-P(\dfrac{-54}{\dfrac{324}{\sqrt{83}}}$

hence, the required probability = 0.129

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2 years ago

Select the correct answer

leonid [27]

Answer: C.156

Step-by-step explanation:

Given: Total seashells = 160

mean = 120

population standard deviation = 26 grams

The probability that the seashells weigh at least 68 grams :-'

$P(X\geq68) =P(\dfrac{x-\mu}{\sigma}\geq\dfrac{68-120}{26})\\\\=P(z\geq-2)\\\\=P(z$

Total seashells weigh at least 68 grams = 0.9772 x 160 = 156.352≈ 156

Hence, the correct option is C.156

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2 years ago

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alexandr1967 [171]

Answer:

Hey there!

This is not a valid experiment because the sunshine each section received were not equal.

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