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lilavasa [31]
2 years ago
15

Is 24/40 4/5 a true proportion?

Mathematics
1 answer:
cupoosta [38]2 years ago
5 0

Answer:

no

Step-by-step explanation:

24 x 5 = 120

40 x 4= 160

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Which transformation maps hexagon 1 into 3?
umka2103 [35]
Let's look at the possibilities:

1. Reflection along the y-axis and rotation of 180 degrees by the origin 0. (Gives us 4 and then 2 in the end)

2. Reflection along the y-axis and reflection along the x-axis. (Gives us 4 and then 3 in the end)

3. Reflection along the x-axis and rotation 90 degrees by the origin 0. (Gives us 4 and then 1 in the end)

4. Rotation of 270 degrees by the origin 0. (Gives us 2 in the end)

Option 2 is the answer.

Best of luck!
5 0
2 years ago
Santiago hopes to buy a 4 horse trailer for about $12000. Describe all the numbers that when rounded to the nearest hundred are
jok3333 [9.3K]
To round a number to the nearest hundred, we count two places to the left of the decimal point, or from the last digit if the number is a whole number.

If the second digit from the last digit is upto 5, we add 1 to the preceding digit and we complete the last two numbers with zeros.

Therefore, any number from 11,950 to 12,049, will result to 12,000 when rounded to the nearest hundred.
8 0
2 years ago
Read 2 more answers
Travis is considering taking out a 20-year loan with monthly payments of
d1i1m1o1n [39]

Answer:

travis monthly payment $350 the amt of the loan that he is considering taking out would be less than $79,504.54

Step-by-step explanation:

Apex

8 0
2 years ago
Read 2 more answers
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
1 year ago
Read 2 more answers
Solve for $a$: $3a-7(3-a)=5$. Express your answer as a common fraction in simplest form.
SashulF [63]

Answer:

2.6

Step-by-step explanation:

just put one part of the equation in y1 and the other in y2 and hit 2nd trace 5 an hit enter 4 times

then it will bring a graph hit enter 3 time again and it will show u the answer at the bottom left

3 0
2 years ago
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