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sergey [27]
2 years ago
11

A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of

healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects. Assume that we want to treat 7 healthy humans with this new drug and we have 11 suitable volunteers available. Complete parts​ (a) through​ (c) below.a. If the subjects are selected and treated in sequence, so that the trial is discontinued if anyone displays adverse effects, how many different sequential arrangement are possible if 7 people are selected from the 9 that are available? Choose the correct answer below. A. 181,440 B. 362,880 C. 5,040 D. 36b. If 7 subjects are selected from the 9 that are available, and the 7 selected subjects are all treated at the same time, how many different treatment groups are possible? There are_________ different treatment groups possible c. If 7 subjects are randomly selected and treated at the same time, what is the probability of selecting the 7 youngest subjects? P(selecting the 7 youngest subjects)_________(Type an integer or a simplified fraction.)
Mathematics
1 answer:
navik [9.2K]2 years ago
6 0

Answer:

A clinical test on humans of a new drug is normally done in three phases. Phase I is conducted with a relatively small number of healthy volunteers. For​ example, a phase I test of a specific drug involved only 7 subjects.

Step-by-step explanation:

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Nicole bought six pounds of apples at $1.50 per pound. The store had a discount of $2 off her total purchase. Nicole and her fri
Andru [333]

Answer:

Step-by-step explanation:

Total amount of apples that Nicole bought was 6 pounds.

Each pound of apple cost $1.50

This means that the total cost of the 6 pounds of apple that Nicole bought would be

6 × 1.5 = $9

The store had a discount of $2 off her total purchase. This means that the amount that was paid is

9 - 2 = $7

If Nicole and her friend then divided the cost of the purchase evenly, let x represent the amount that each of them would pay. Therefore, the expression that can be used to determine how much Nicole and her friend each paid for the apples would be

x = 7/2

6 0
2 years ago
Sanya noticed that the temperature was falling at a steady rate of 1.4 degrees every hour after the time that she first checked
kakasveta [241]

Answer:A not b or c or d A!!

Step-by-step explanation:

4 0
2 years ago
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A collection of quarters and nickels contains at least 42 coins and is worth at most $8.00. If the collection contains 25 quarte
Elenna [48]

Answer:

17

35

Step-by-step explanation:

9 0
2 years ago
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You take the four Aces, four $2$'s, and four $3$'s from a standard deck of 52 cards, forming a set of $12$ cards. You then deal
kap26 [50]

Answer:

Probability each player gets an ace, a $2 and a $3 = 0.0374

Step-by-step explanation:

The total number of ways to divide the card in triples among four players = 369600 ways

The total number of ways to share the cards such that no card is repeated in each triple = 13824 ways

Probability each player gets an ace, a $2 and a $3 = 13824/369600

Probability each player gets an ace a $2 and a $3 = 0.0374

Note: Further explanation is provided in the attachment.

8 0
1 year ago
Prove that sinA-sin3A+sin5A-sin7A/cosA-cos3A-cos5A+cos7A= cot2A
MAVERICK [17]
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.

We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)

N = -(sin7A - sinA) + sin5A - sin3A
    = -2cos4A*sin3A + 2cos4A*sinA
    = 2cos4A(sinA - sin3A)
    = 2cos4A*2cos(2A)sin(-A)
    = -4cos4A*cos2A*sinA

D = cos7A + cosA - (cos5A + cos3A)
   = 2cos4A*cos3A - 2cos4A*cosA
   = 2cos4A(cos3A - cosA)
   = 2cos4A*(-2)sin2A*sinA
   = -4cos4A*sin2A*sinA

Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
       = cos2A/sin2A
      = cot2A

This verifies the identity.
4 0
2 years ago
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