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storchak [24]
2 years ago
7

What is the product of 5.86 × 10–7 and 3.1 × 104 1. Write the expression: (5.86 × 10–7)(3.1 × 104) 2. Rearrange the expression:

(5.86 × 3.1)(10–7 ∙ 104) 3. Multiply the coefficients: (18.166)(10–7 ∙ 104) 4. Apply the product of powers: 18.166 × 10-3 5. Write in scientific notation: 1.8166 × 10n What is the value of n in the scientific notation of the product? n =
Mathematics
2 answers:
Alex Ar [27]2 years ago
6 0

Answer:

this is the answer a good question

Soloha48 [4]2 years ago
4 0

Answer:

-2

Tell Doja Cat i said hi

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Jaime make $8.20 on hour in his part-time job. He made $53.30 last week. How many hours did he work.
andrew11 [14]

Answer:

he worked for 6 hours and 30 min

Step-by-step explanation:

what you do is take 53.30 and divide it by 8.20

4 0
2 years ago
There are cars and motorcycles in a campus parking lot. The parking attendant noticed there are a total of 294 tires and a total
malfutka [58]
This can't work because if there are 60 cars that means there are 240 car wheels and then 25 bikes means 50 bike wheels for a total of 290 wheels, if there was 1 more car then it would be 86 cars and motorcycles with 294 wheels or 2 more bikes would mean 87 cars and motorcycles with 294 wheels
4 0
2 years ago
Mike is preparing refreshments for a party. To make a smoothie, he will mix 3 1⁄2 quarts of strawberry puree with 2 pints of lem
Shkiper50 [21]
Let's convert all volumes into pint:

1 Quart  = 2 pints → 3.5 quart of strawberry = 2 x 3.5 = 7 pints Strawberry
1 Gallon = 8 pints →1.25 Ga. water = 1.25 x 8 = 10 pints Water
2 pints of limonade = 2 pints of limonade 

Add up all pints Total = 7+10+2 = 19 pints of smoothie

Or in quart 9.5

Or in Gal 2.375

7 0
2 years ago
Read 2 more answers
Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below. Find the 93% conf
kobusy [5.1K]

Answer:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We have the following data given:

\bar X_1 = 9.2 , \bar X_2 = 8.8, \sigma_1= 0.3, n_1 = 27, \sigma_2 = 0.1, n_2 = 30

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 93% of confidence, our significance level would be given by \alpha=1-0.93=0.07 and \alpha/2 =0.035. And the critical value would be given by:  

z_{\alpha/2}=-1.811, z_{1-\alpha/2}=1.811  

The confidence interval is given by:

(\bar X_1 -\bar X_2) \pm z_{\alpha/2} \sqrt{\frac{s^2_1}{n_1}+\frac{s^2_}{n_2}}

And replacing we got:

(9.2 -8.8) - 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.2903

(9.2 -8.8) + 1.811 \sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}= 0.5097

And the confidence interval for the difference of means would be given by:

0.2903 \leq \mu_1 -\mu_2 \leq 0.5097

4 0
2 years ago
Which expressions are equivalent to the one below? Check all that apply.
mestny [16]

Answer:

c

Step-by-step explanation:

log2-log 6=log(2/6)=log (1/3)

4 0
1 year ago
Read 2 more answers
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