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hoa [83]
2 years ago
15

The circle below is centered at the point (-3/4) and has a radius of length 3 what is its equation??

Mathematics
2 answers:
Agata [3.3K]2 years ago
6 0
{x-(-3/4)}^2=3^2
(x+3/4)^2=9
{(4x+3)/4}^2=9
(4x+3)^2/16=9
(4x+3)^2=9*16
16x^2+2*4x*3+3^2=144
16x^2+24x+9=144
16x^2+24x+9-144=0
16x^2+24x-135=0
Juli2301 [7.4K]2 years ago
4 0

Answer:

  (x+3)^2+(y-4)^2=9

Step-by-step explanation:

We are given a circle which is centered at the point (-3,4) and has a radius of length 3.

We have to find the equation of the circle.

The equation of circle centered at (a,b) and radius r is:

   (x-a)^2+(y-b)^2=r^2

Here a=-3 , b=4 and r=3

Hence, equation of circle is:

   (x+3)^2+(y-4)^2=3^2

      (x+3)^2+(y-4)^2=9

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In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

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