You would multiply by 1.7
Answer:
0.08 ounces is interpreted as the Mean Absolute Deviation and this means that
the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces.
Step-by-step explanation:
Mean Absolute Deviation of a data set is defined as the distance or the deviation between a given data set and the calculated mean.
Mean Absolute Deviation tells us about how much a data set varies from it's mean.
From the above question, we are told that after weighing 48 eggs we have a mean of 2.1 ounces and mean deviation of 0.08 ounces
Therefore this means that the various weights of each of the 48 eggs deviates from the mean of the egg (2.1 ounces)by 0.08 ounces
<span><span>(<span>sinx</span>−<span>tanx</span>)</span><span>(<span>cosx</span>−<span>cotx</span>)</span></span>
<span>=<span>(<span>sinx</span>−<span><span>sinx</span><span>cosx</span></span>)</span><span>(<span>cosx</span>−<span><span>cosx</span><span>sinx</span></span>)</span></span>
<span>=<span>sinx</span><span>(1−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(1−<span>1<span>sinx</span></span>)</span></span>
<span>=<span>sinx</span><span>(<span><span>cosx</span><span>cosx</span></span>−<span>1<span>cosx</span></span>)</span><span>cosx</span><span>(<span><span>sinx</span><span>sinx</span></span>−<span>1<span>sinx</span></span>)</span></span>
<span>=<span><span>sinx</span><span>cosx</span></span><span>(<span>cosx</span>−1)</span><span><span>cosx</span><span>sinx</span></span><span>(<span>sinx</span>−1)</span></span>
<span>=<span>(<span>cosx</span>−1)</span><span>(<span>sinx</span>−1<span>)</span></span></span>
Answer:
Therefore, we use the linear depreciation and we get is 17222.22 .
Step-by-step explanation:
From Exercise we have that is boat $250,000.
The straight line depreciation for a boat would be calculated as follows:
Cost boat is $250,000.
For $95,000 Deep Blue plans to sell it after 9 years.
We use the formula and we calculate :
(250000-95000)/9=155000/9=17222.22
Therefore, we use the linear depreciation and we get is 17222.22 .
The confidence interval would be (0.122, 0.278).
We first find our z-score. We want a 95% confidence interval:
0.95/2 = 0.475
Looking this up in the z-table, (http://www.statisticshowto.com/tables/z-table/) we see the z-score is 1.96.
The formula we will use is:
In this problem, p = 20/100 = 0.2, and n=100:
