Let's find the area of the base.
It's a rectangle that's 3.8 by 4.8, so let's multiply.
3.8×4.8=18.24
We have two different triangles.
Triangle one has a height of 2.6 and base of 4.8. But there are two of them.
2.6×4.8×0.5=6.24×2= 12.48; this is the area of two triangles.
Another set of triangles has a height of 2.9 and a base of 3.8.
2.9×3.8×0.5=5.51×2=11.02
Let's add all the areas together.
18.24+12.48+11.02
41.74
The surface area is 41.74 m², so the third option.
Please rewrite this equation(s) using parantheses than needed
thank you
This is late, but for anyone searching the answer up in the future, the answer on Edg.enuity is the last one - where the graph starts out as a horizontal line, then decreases and touches the x-axis, then increases again.
Good luck on your assignment !!
1. A straight line segment can be drawn joining any two points.
2. Any straight line segment can be extended indefinitely in a straight line.
3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.
4. All right angles are congruent.
5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.
We know the triangle is an isosceles triangle. So, we use the Pythagorean Theorem.
a^2+b^2=c^2
The c would be 22, because it's the longest edge. Now find a or b. They are the same, that is how you find the two sides of the triangle for part A.
To find the area of the triangle, the forumla is a=hb/2
Plug in the numbers for that formula and the answer would be found for part B.
I hope I helped.
