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Alecsey [184]
2 years ago
12

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Mathematics
1 answer:
Tema [17]2 years ago
4 0
Your x values are 1.24 and -0.404.
First you need to make the equation equal 0, and you can do this simply by subtracting 5x, so you get
6x² - 3 - 5x = 0
The quadratic formula is (-b +- √b² - 4ac)/2a, where a is the x², b is the x, and c is the value. This means we can just substitute it in.
You find the value of the part inside the square root, which is -5² - 4 × 6 × -3 = 97. Now we can use this to substitute in to (5 +- √97)/12. We can do it with the plus sign, and get 1.24, and then with the subtract sign and get -0.404.

I hope this helps!
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Help? Use the law of sines to find the length of side c
Ahat [919]
<h3>✽ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ✽</h3>

➷ a/sinA = c/sinC

Substitute in the values:

37/sin(42) = c/sin(41.5)

Multiply both sides by sin(41.5)

37/sin(42) x sin(41.5) = c

Solve:

c = 36.63999457

The correct answer would be C. 36.64

<h3><u>✽</u></h3>

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5 0
2 years ago
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The graph shows the linear relationship between the height of a plant (in centimeters) and the time (in weeks) that the plant ha
bija089 [108]
I found a graph with the same problem, so I guess this is the graph to be based on. To find the rate, just determine the slope between any two points along the line. Suppose these points are: (30,10) and (50,20).

Slope = (20 - 10)/(50 - 30) = 1/2

<em>The correct answer should be: the rate of change is 1 cm per 2 weeks, or 1/2.</em>

5 0
2 years ago
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A craftsman can sell 10 jewelry sets for $500 each. He knows
liraira [26]

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning=\text{Price of each set}\times \text{no of set}

Earning =(500-25n)(10+n)

E=5000+500n-25n^2-250n

differentiate to get the maximum value

\frac{dE}{dn}=-50n+250

Equate \frac{dE}{dn} to get maximum value

-50n+250=0

n=\frac{250}{50}

n=5

Thus must sell 5 extra set to maximize its earnings.

5 0
2 years ago
The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

(0.36143)(0.36143) = 0.13063

4 0
2 years ago
-6y + 3(12y) = 20(y - 1) + 15 is it true?
xxMikexx [17]

Answer:

y= - 1/2 (negative half) =  -0.5

Step-by-step explanation:

−6y+3(12y)=20(y−1)+15

Multiply 3 and 12 to get 36.

−6y+36y=20(y−1)+15

Combine −6y and 36y to get 30y.

30y=20(y−1)+15

Use the distributive property to multiply 20 by y−1.

30y=20y−20+15

Add −20 and 15 to get −5.

30y=20y−5

Subtract 20y from both sides.

30y−20y=−5

Combine 30y and −20y to get 10y.

10y=−5

Divide both sides by 10

y= -5/10

Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .

5 0
2 years ago
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