Let's call Tacos t and Enchiladas e.
Lily paid $9 for 2t and 3e
Alex paid $12.50 for 3t and 4e.
Thus the equations would be.
Lily paid $9 for 2t and 3e
Alex paid $12.50 for 3t and 4e.
Thus the equations would be.
15,000 blue trout were released into the Meherrin River for a scientific study. The function, f(x) = 15,000 (98)x , represents t
1 answer:
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Answer:
At the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.
Step-by-step explanation:
We are given that the mean gross annual incomes of certified welders are normally distributed with the mean of $20,000 and a standard deviation of $2,000.
The ship building association wishes to find out whether their welders earn more or less than $20,000 annually.
<u><em>Let </em></u><u><em> = mean gross annual incomes of certified welders</em></u>
So, Null Hypothesis, :
= $20,000
Alternate hypothesis, :
$20,000
Here, null hypothesis states that the mean income of welders is equal to $20,000.
On the other hand, alternate hypothesis states that the mean income of welders is not $20,000.
Also, the test statistics that would be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;
T.S. = ~ N(0,1)
where, = sample mean income
= population standard deviation = $2,000
n = sample size
Now, at the 0.10 level of significance the z table gives critical values of -1.645 and 1.645 for two-tailed test.
Let the total sum of the scores of the first class of 35 students be a. The mean is 74.3 .
So
Also, let the total sum of the scores of the second class of 28 students be b. The mean is 67.6 .
so
The combined group has 35+28=63 students. The sum of their scores is
a+b=2600.5+1892.8=4493.3
Thus, the mean of the combined group is
So
Also, let the total sum of the scores of the second class of 28 students be b. The mean is 67.6 .
so
The combined group has 35+28=63 students. The sum of their scores is
a+b=2600.5+1892.8=4493.3
Thus, the mean of the combined group is