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kotegsom [21]
2 years ago
7

Paper plates cost $8 per package and plastic utensils cost $5 per package. Your supplier delivers 15 packages for a total cost o

f $90.

Mathematics
1 answer:
Fittoniya [83]2 years ago
8 0
To find the total of what you sold for each package, you'll need to write two equations. Know that x = paper plate packages and y = utensil packages.
First, x + y = 15 shows that there has to be fifteen packages, and 8x + 5y = 90 shows the $ made from selling a certain number of packages.
Next, you can solve by substitution, so change x + y = 15 to y = 15 - x.

To find our x, substitute the y in 8x + 5y = 90 to get
8x + 5(15 - x) = 90
Distribute: 8x + 75 - 5x = 90
Combine the X's and subtract the 75: 3x = 15
Divide the 3: x = 5

Now with our x, we can put 5 into the original equation x + y = 15 to get 5 + y = 15. Subtracting the 5, we get y = 10.

So, you have delivered 5 paper plate packages and 10 utensil packages.
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Ahmed doubled his savings, then deposited another hundred dollars. Let s represent the amount he originally had in savings. Whic
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Do the opposite of what you did in reverse order.

so add 100 and divide by 2 in that order.

(80 + 100)/2
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4(5x−3)+5x+5 = 118<br><br> solve for x
EleoNora [17]

Answer:

x=1+2/15

Step-by-step explanation:

4(5x-3)=5x+5=118

We move all terms to the left:

4(5x-3)-(5x+5)=0

We multiply parentheses

20x-(5x+5)-12=0

We get rid of parentheses

20x-5x-5-12=0

We add all the numbers together, and all the variables

15x-17=0

We move all terms containing x to the left, all other terms to the right

15x=17

x=17/15

x=1+2/15

   

   

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1 year ago
A recent poll of 85 randomly selected cable subscribers found that 39% would be willing to pay extra for a new nature channel. T
adoni [48]
The mean is 85*0.39 = 33.15, while the standard error is sqrt(0.39*0.61/85) = 0.0529. Using the z-score of 1.96, the confidence interval is:33.15 +/- 1.96*0.0529 = (33.05, 33.25)By dividing by 85, this corresponds to a proportion of:(0.3888, 0.3912)

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How to factor quadratics like <br> 2<br> 3x^+31x+36
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Answer:

3(x32+12)

Step-by-step explanation:

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To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne
Naily [24]

Answer:

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

\hat p=\frac{67}{150}=0.447 estimated proportion of applicants who request financial aid

p_o=0.35 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:  

Null hypothesis:p\leq 0.35  

Alternative hypothesis:p > 0.35  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.491)=0.0064  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0
2 years ago
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