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bulgar [2K]
2 years ago
10

In a family there are five sons. The oldest son is 11 3/4 years old, and every next younger brother is younger than the next by

2 7/12 years. How old is the youngest brother? In how many years would another son be born if this rule still applies? Can you give the answer in years and months?
Mathematics
2 answers:
timama [110]2 years ago
5 0

Answer:

the youngest brother is of 2 years and 5 months

if this rule still applies, the next son will be born in 2 months.

Step-by-step explanation:

Given that:

Oldest son= 11 3/4 years old = 11 years 3/4 (12) months = 11 years 9 months

Difference = 2 years 7/12(12) months = 2 years 7 moths

So for finding the age of youngest brother:

Subtract the difference others from age of oldest:

= 11 years 9 months - 4(2 years 7 months)

= 11 years 9 months - 9 years 4 months

=  2 years 5 months

So the youngest brother is of 2 years and 5 months

if this rule still applies, the next son will be born in 2 months.

i hope it will help you!

masha68 [24]2 years ago
5 0

Answer:

im pretty sure this is correct: the youngest brother is 1 year and 5 months, and another son will be born in  1 year and 2 months

Step-by-step explanation:

welp

Im bad at explaining but:

<u>Part 1</u>

a-oldest = x = 11 3/4

b- x-2 7/12

c- x-2(7/12)

d - x-3(7/12)

e - x-4(7/12) = 1 5/12

<u>Part 2</u>

1 5/12 - 2 7/12 = 1 1/6 aka 1 year and 2months

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D. -6m²n² + 10m²n + 8mn² - 10mn

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1 year ago
Let X denote the number of bars of service on your cell phone whenever you are at an intersection with the following probabiliti
lorasvet [3.4K]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: number of bars of service on your cell phone.

The posible values of this variable are {0, 1, 2, 3, 4, 5}

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b.

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c.

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d.

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This expression means "the probability of having at most (or less or equal to) 3.5 service bars", this variable doesn't have the value 3.5 in its definition range so you have to look for the accumulated probability until the lesser whole number. This expression includes the probabilities of X=0, X=1, X=2, and X=3, you can express it as the accumulated probability until 3, F(3):

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I hope it helps!

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