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OLEGan [10]
1 year ago
9

Alyssa wants to know the gas mileage of her new car. She kept track of the number of miles she traveled and the number of gallon

s she used. Which method and reasoning can Alyssa use to calculate the gas mileage in miles per gallon?
Miles Traveled : 243.8
Gallons Used : 7.71

A. 243.8 miles × 7.71 gallons
because multiplying a quantity with units of miles by a quantity with units of gallons gives a quantity with units of miles per gallon.

B. 243.8 miles - 7.71 gallons
because subtracting a quantity with units of gallons from a quantity with units of miles gives a quantity with units of miles per gallon.

C. 7.71 gallons ÷ 243.8 miles
because dividing a quantity with units of gallons by a quantity with units of miles gives a quantity with units of miles per gallon.

D. 243.8 miles ÷ 7.71 gallons
because dividing a quantity with units of miles by a quantity with units of gallons gives a quantity with units of miles per gallon.
Mathematics
1 answer:
Anna [14]1 year ago
3 0

Answer:

D


Step-by-step explanation:

Since Alyssa wants to know her gas mileage, which is MILES PER GALLON, she will need to divide total miles by total gallons.

"per gallon" means per 1 unit of gallon, which we will get ONLY IF WE DIVIDE by TOTAL NUMBER OF GALLONS, hence we get "per unit of gallon".

<u>So we need to divide 243.8 miles by 7.71 gallons to get Alyssa's gas mileage.</u>

Answer choice D is right.

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Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC =\frac{b}{a-c}

Step-by-step explanation:

According to midpoint formula

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the coordinate (x,y) of mid point of line PQ is given by

x=\frac{x_{1} +x_{2} }{2} and y=\frac{y_{1} +y_{2} }{2}

now from the given diagram A is the mid point of line joining  R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

x=\frac{0+2a}{2}= a and y=\frac{0+2b}{2} =b

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

x= \frac{2c+2c}{2} =2c and y=\frac{2d+0}{2} =d

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P (x_{1} ,y_{1} ) and Q (x_{2} ,y_{2} )

then the slope of PQ =\frac{y_{2} -y_{1} }{x_{2}-x_{1}  }

hence slope of AD= \frac{0-b }{c-a}

                                 =\frac{-b}{c-a}

                                  =\frac{-b}{-(a-c)}

                                  =\frac{b}{a-c}

and slope of BC  =\frac{d-(b+d)}{2c-(a+c)}

                            =\frac{d-b-d}{2c-a-c}

                             =\frac{-b}{c-a}

                              =\frac{b}{a-c}

so we have

slope of AD and BC =\frac{b}{a-c}

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