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2 years ago

8

Kendra made a scaled copy of the following square. She used a scale factor less than 111. What could be the side length of the s

caled copy of the square.

1 answer:

ololo11 [35]2 years ago

4 0

Answer:

2 units

1/4 unit

5 units

Step-by-step explanation:

Khan ^w^'

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What are these fractions in simplest form?

Anton [14]

$\frac{16y^{3}}{20y^{4}} = \frac{4}{5y}$
$\frac{6xy}{16y} = \frac{3x}{8}$
$\frac{abc}{10abc} = \frac{1}{10}$
$\frac{mn^{2}}{pm^{5}n} = \frac{n}{pm^{4}}$
$\frac{12h^{3}k}{16h^{2}k^{2}} = \frac{3h}{4k}$
$\frac{8x}{10y} = \frac{4x}{5y}$
$\frac{24n^{2}}{28n} = \frac{6n}{7}$
$\frac{30hxy}{54kxy} = \frac{5h}{9k}$
$\frac{5jh}{15jh^{3}} = \frac{1}{3h^{2}}$
$\frac{20s^{2}t^{3}}{16st^{5}} = \frac{5s}{4t^{2}}$

8 0

2 years ago

In professional basketball games during 2009-2010, when Kobe Bryant of the Los Angeles Lakers shot a pair of free throws, 8 time

ziro4ka [17]

Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot Made Second shot missed Total

__________________________________________________

Made 152 33 185

Missed 37 8 45

__________________________________________________

Total 189 41 230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot Made Second shot missed

_____________________________________________________

Made 189(185)/230=152.0217 41(185)/230=32.9783

Missed 189(45)/230=36.9783 41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

$\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}$

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

$\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881$

Now with the calculated value we can find the degrees of freedom

$df=(r-1)(c-1)=(2-1)(2-1)=1$ on this case r means the number of rows and c the number of columns.

Now we can calculate the p value

$p_v =P(\chi^2 >0.00008881)=0.9925$

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

5 0

2 years ago

Matt can buy and 8 ounce jar of salsa for $2.79 or a 15 ounce jar of salsa for $5.54 which jar has the best unit rate

sasho [114]

Answer:

8 ounce jar

Step-by-step explanation:

We divide the price by the number of ounces to find the unit rate or cost per one ounce.

2.79/8=0.34875

5.54/15=0.3693

The 8 ounce jar has the best unit rate with a lower cost per ounce.

5 0

2 years ago

Which is a perfect square? 6 Superscript 1 6 squared 6 cubed 6 Superscript 5 Mark

Mazyrski [523]

Answer:

$6^2$

Step-by-step explanation:

The square root of a perfect square is a rational number.

So let us take the square root of each number to see which is a rational number.

$\sqrt{6^1}=\sqrt{6}$ ......irrational

$\sqrt{6^2}=6$ ......rational

$\sqrt{6^3}=6\sqrt{6}$ .........irrational

$\sqrt{6^5}=36 \sqrt{6}$ irrational.

Therefore $6^2$ is a perfect square

3 0

2 years ago

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A semicircular flower bed has a diameter of 3 metres. What is the area of the flower bed?

Yuri [45]

The area of circle is

$A_{\text{circle}}=\pi r^2.$

Then the area of semicircular region is

$A_{\text{semicircular region}}=\dfrac{1}{2} \pi r^2.$

If r=3 m, you have

$A_{\text{semicircular region}}=\dfrac{1}{2} \pi \cdot 3^2=\dfrac{9\pi}{2}=4.5\pi \approx 14.13$ sq. m.

Answer: $A_{\text{semicircular region}}=4.5\pi \approx 14.13$ sq. m.

3 0

2 years ago

Read 2 more answers