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erastova [34]
2 years ago
15

−12x−5y=40 12x−11y=88 ​ x= y=

Mathematics
1 answer:
Nezavi [6.7K]2 years ago
6 0
Add the two equations and use the elimination method. The x term will "cancel out" to be able to solve for the y term.

STEP 1
−12x−5y=40
12x−11y=88 ​
x terms "cancels out"; add y terms

-16y= 128
divide both sides by -16

y= -8


STEP 2
substitute y value into either original equation

12x−11y=88 ​

12x - 11(-8)= 88

12x + 88= 88
subtract 88 from both sides

12x= 0
divide both sides by 12; 0 divided by any number is 0

x= 0


ANSWER: x= 0; y= -8

Hope this helps! :)
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The question doesn’t provide any figures.
Let’s put some in as an example. Let the actual merry-go-round be circular with a diameter of 20 feet, while the model is one foot in diameter. So the ratio of the actual ride and it’s model is 20:1. The area of the base of the actual ride is 100π sq ft. The area of the base of the model is π/4 sq ft. We expect the ratio of these areas to be 20²=400. 100π/(π/4)=400.
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2 years ago
Louis is climbing steps to the top of a monument. After climbing 15 steps, Louis stops to tie his shoe. If there is a total of 7
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2 years ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

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2 years ago
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Answer:

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Step-by-step explanation:

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y = $99.97 (rounded)
7 0
2 years ago
Read 2 more answers
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