The choir members need $1500, but they have $600. Therefore, they need $1500-$600=$900 more.
Call a the average amount raised by a member. We see that 30a >= $900. Dividing by 30, we find that a >= $30, so the average member must raise at least $30.
Answer:
'Well, Charles was bad again today.' He grinned enormously.” "'Well, he certainly likes kindergarten,' I said. 'He talks about it all the time.'"
Step-by-step explanation:
Let's first write each step of the procedure:
Step 1:
group the x terms together and the terms and together, and move the constant term to the other side of the equation:
x² + 12x + y² + 2y = 1
Step 2:
determine (b ÷ 2) 2 for the x and y terms.
(12 ÷ 2) 2 = 36
and
(2 ÷ 2) 2 = 1
Step 3:
add the values to both sides of the equation.
x2 + 12x + 36 + y2 + 2y + 1 = 1 + 36 + 1
Step 4:
write each trinomial to binomial squared, and simplify the right side.
(x + 6) 2 + (y + 1) 2 = 38
Answer:
the last step is:
(x + 6) 2 + (y + 1) 2 = 38
Answer:
$95.78
Step-by-step explanation:
f(t) = 300t / (2t² + 8)
t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.
$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt
$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt
$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt
$T₂ = 75 ln(t² + 4) |₅¹⁰
$T₂ = 75 ln(104) − 75 ln(29)
$T₂ ≈ 95.78
