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svetoff [14.1K]
2 years ago
6

3.The monopolist faces a demand curve given by D(p) = 10p-3 . Its cost function is c(y) = 2y. What is its optimal level of outpu

t and price?.
Mathematics
1 answer:
shusha [124]2 years ago
5 0
<span>-> R (y) = (10y -3) 2y = 20y² - 6y -> R' (y) = 40y - 6 Optimal level of output when R' (y) = C'(y) -> 40y - 6 = 2 => 40y = 8 => y = 8/40 = .2 by using differential calculus w got its optimal level and price</span>
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At a red-tag sale, all items with red tags have been marked down by 49%. What should be the sale price of a DVD player having a
vampirchik [111]
Original price was $234.95
49% marked down = $234.95 *49 / 100 = $115.13

So now the sale price = original price - price of 49% marked down

sale price = $234.95 - $115.13 = $119.82

Answer: sale price of a DVD player having a red tag marked down by 49% should be $119.82
8 0
2 years ago
The formula T = 2 pi StartRoot StartFraction L Over 32 EndFraction EndRoot relates the time, T, in seconds for a pendulum with t
Serga [27]

Answer:t

Step-by-step explanation:

8 0
2 years ago
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A segment has endpoints A (-1, 1) and B (8, 4) . If the segment is divided into four equal parts, the coordinates of the point c
riadik2000 [5.3K]

Line is divided into 4 equal parts.

we have to find a point which is closest to point A.

So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)

Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3

\left ( \frac{m_1x_2+m_2x_1}{m_1+m_2}  , \frac{m_1y_2+m_2y_1}{m_1+m_2} \right )

= \left ( \frac{1*8+3*(-1)}{1+3}  , \frac{1*4+3*1}{1+3} \right )

= \left ( \frac{8-3}{4}  , \frac{4+3}{4} \right )

= \left ( \frac{5}{4}  , \frac{7}{4} \right )

So the final answer is \left ( \frac{5}{4}  , \frac{7}{4} \right ).

6 0
2 years ago
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Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
alexdok [17]

Answer:

The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.

There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

ANSWER = 42

The forty two numbers are 58 ,59, 60, 61......98, 99

7 0
2 years ago
Read 2 more answers
What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0? Use u substitution and the quadratic formula to solve.
zvonat [6]

Answer:

x=-2.38

x=-4.62


Step-by-step explanation:

The question is  (2x+3)^2+8(2x+3)+11=0

<em>We let u=2x+3, so the equation becomes:</em>

u^2+8u+11=0

Where a=1, b=8, c=11


Putting it in the quadratic formula, we have:

<u>Quadratic formula:</u> \frac{-b+-\sqrt{b^2-4ac} }{2a}

Substituting we have: \frac{-8+-\sqrt{(8)^2-4(1)(11)} }{2(1)}\\=\frac{-8+-\sqrt{20} }{2}\\=\frac{-8+-2\sqrt{5} }{2}\\=-4+\sqrt{5}, -4-\sqrt{5} }


<em>We let u=2x+3, so x is:</em>

<em>u=2x+3\\(-4+\sqrt{5})=2x+3\\x=\frac{-7+\sqrt{5}}{2}=-2.38</em>

<em>and</em>

<em>u=2x+3\\(-4-\sqrt{5})=2x+3\\x=\frac{-7-\sqrt{5}}{2}=-4.62</em>


The solutions of the equation is x=-2.38 (rounded to 2 decimal places), and x=-4.62 (rounded to 2 decimal places)

6 0
2 years ago
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