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babymother [125]
2 years ago
10

In a West Texas school district the school year began on August 1 and lasted until May 31. On August 1 a Soft Drink company inst

alled soda machines in the school cafeteria. It found that after t months the machines generated income at a rate of f(t) = 300t/2t2 + 8 dollars per month. Find the total income, $Tscc, produced during the second semester beginning on January 1.
Mathematics
1 answer:
WINSTONCH [101]2 years ago
3 0

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August.  t = 1 corresponds to the end of August.  t = 2 corresponds to the end of September.  So on and so forth.  So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

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Answer:

4 \sqrt{2} i

Step-by-step explanation:

We want to find the sum of

\sqrt{ - 2}  +  \sqrt{ - 18}

We can rewrite this as

\sqrt{ 2 \times  - 1}  +  \sqrt{ 18 \times  - 1}

This becomes;

\sqrt{2}  \times  \sqrt{ - 1}  +  \sqrt{18}  \times  \sqrt{ - 1}

Recall that;

i =  \sqrt{ - 1}

This implies that;

\sqrt{2} i + 3 \sqrt{2} i

Combine like terms:

4 \sqrt{2} i

3 0
1 year ago
5 equally sized boxes of cake mix fell off the back of Jake's truck. Together they weigh 925.98 pounds. How much does each ball
uysha [10]

we are given

5 equally sized boxes of cake mix fell off the back of Jake's truck

it means that

total number of balls =5

Together they weigh 925.98 pounds

total weighs =925.98 pounds

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now, we can plug values

each ball weighs =\frac{925.98}{5}

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4 0
1 year ago
What is the midpoint of the x-intercepts of f(x) = (x – 4)(x + 4)?
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9 0
2 years ago
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The sum of Jim's weight and Bob's weight is 180 pounds. If you subtract Jim's weight from Bob's weight, you get half of Bob's we
Furkat [3]

Answer:

120 pounds

Step-by-step explanation:

We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:

j + b = 180

b - j = 1/2b

Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)

b - j = \frac{b}{2}\\\frac{b}{2} - j = 0

Now we can solve using the process of elimination.

b + j = 180\\\\\frac{b}{2} - j = 0\\\\b + \frac{b}{2} = 180\\\\b + b \cdot 2 = 180\cdot 2\\3b = 360\\b = 120

Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.

120 + j = 180\\j = 180-120\\j = 60

So Bob weighs 120 pounds and Jim weight 60 pounds.

Hope this helped!

4 0
2 years ago
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