Answer:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above, let μ represent the average test scores for the teaching methods:
The null hypothesis is that all the different teaching methods have the same average test scores.
H0: μ1 = μ2 = μ3 = μ4 = μ5
The alternative hypothesis is that at least one of the teaching methods have a different mean.
Ha: at least one mean is different. (μ1 ≠ μi)
Answer: SSS
Proof:
In ΔMLQ and ΔNPQ,
MQ = NQ (given) S
Since Q is the midpoint of LP, by definition, LQ = QP (S)
LM = PN (given) S
∴ ΔMLQ ≡ ΔNPQ (SSS)
Answer:
100 percent increase
Step-by-step explanation:
1st garden
Length = 6 ft
Width = 4 ft
Perimeter = 2 (l+w)
= 2 (6+4) = 2(10) = 20
2nd garden
The length and width are 2 times the 1st garden
Length = 2 *6 = 12
Width = 2 *4 = 8
Perimeter = 2 (l+w)
= 2 (12+8) = 2(20) = 40
Percent change = (new - old )/old * 100 percent
The 1st garden is the old garden = 20 and the 2nd garden is the new garden = 40
Substituting in
Percent change = (40-20)/20 = 20/20 =100 *100 percent
= 100 percent increase
10+12+14 = 36
12/36 x 11/35 x 14/34 = 11/255
There's your answer.